How can I figure out the size of a file, in bytes?
#include
unsigned int fsize(char* file){
//what goes here?
}
Based on NilObject's code:
#include <sys/stat.h>
#include <sys/types.h>
off_t fsize(const char *filename) {
struct stat st;
if (stat(filename, &st) == 0)
return st.st_size;
return -1;
}
Changes:
const char
.struct stat
definition, which was missing the variable name.-1
on error instead of 0
, which would be ambiguous for an empty file. off_t
is a signed type so this is possible.If you want fsize()
to print a message on error, you can use this:
#include <sys/stat.h>
#include <sys/types.h>
#include <string.h>
#include <stdio.h>
#include <errno.h>
off_t fsize(const char *filename) {
struct stat st;
if (stat(filename, &st) == 0)
return st.st_size;
fprintf(stderr, "Cannot determine size of %s: %s\n",
filename, strerror(errno));
return -1;
}
On 32-bit systems you should compile this with the option -D_FILE_OFFSET_BITS=64
, otherwise off_t
will only hold values up to 2 GB. See the "Using LFS" section of Large File Support in Linux for details.
**Don't do this (why?):
Quoting the C99 standard doc that i found online: "Setting the file position indicator to end-of-file, as with
fseek(file, 0, SEEK_END)
, has undefined behavior for a binary stream (because of possible trailing null characters) or for any stream with state-dependent encoding that does not assuredly end in the initial shift state.**
Change the definition to int so that error messages can be transmitted, and then use fseek()
and ftell()
to determine the file size.
int fsize(char* file) {
int size;
FILE* fh;
fh = fopen(file, "rb"); //binary mode
if(fh != NULL){
if( fseek(fh, 0, SEEK_END) ){
fclose(fh);
return -1;
}
size = ftell(fh);
fclose(fh);
return size;
}
return -1; //error
}