I\'m using LINQ on an IQueryable returned from NHibernate and I need to select the row with the maximum value(s) in a couple of fields.
I\'ve simplified the bit tha
Addressing the first question, if you need to take several rows grouped by certain criteria with the other column with max value you can do something like this:
var query =
from u1 in table
join u2 in (
from u in table
group u by u.GroupId into g
select new { GroupId = g.Key, MaxStatus = g.Max(x => x.Status) }
) on new { u1.GroupId, u1.Status } equals new { u2.GroupId, Status = u2.MaxStatus}
select u1;
Simply in one line:
var result = table.First(x => x.Status == table.Max(y => y.Status));
Notice that there are two action. the inner action is for finding the max value, the outer action is for get the desired object.
I don't see why you are grouping here.
Try this:
var maxValue = table.Max(x => x.Status)
var result = table.First(x => x.Status == maxValue);
An alternate approach that would iterate table
only once would be this:
var result = table.OrderByDescending(x => x.Status).First();
This is helpful if table
is an IEnumerable<T>
that is not present in memory or that is calculated on the fly.
You can group by status and select a row from the largest group:
table.GroupBy(r => r.Status).OrderByDescending(g => g.Key).First().First();
The first First()
gets the first group (the set of rows with the largest status); the second First()
gets the first row in that group.
If the status is always unqiue, you can replace the second First()
with Single()
.
You can also do:
(from u in table
orderby u.Status descending
select u).Take(1);
More one example:
Follow:
qryAux = (from q in qryAux where
q.OrdSeq == (from pp in Sessao.Query<NameTable>() where pp.FieldPk
== q.FieldPk select pp.OrdSeq).Max() select q);
Equals:
select t.* from nametable t where t.OrdSeq =
(select max(t2.OrdSeq) from nametable t2 where t2.FieldPk= t.FieldPk)