Sort an Array by keys based on another Array?

Question

Is it possible in PHP to do something like this? How would you go about writing a function? Here is an example. The order is the most important thing.

$custo         


        

Answer 1

Without magic...

$array=array(28=>c,4=>b,5=>a);
$seq=array(5,4,28);    
SortByKeyList($array,$seq) result: array(5=>a,4=>b,28=>c);

function sortByKeyList($array,$seq){
    $ret=array();
    if(empty($array) || empty($seq)) return false;
    foreach($seq as $key){$ret[$key]=$dataset[$key];}
    return $ret;
}

Answer 2

A bit late, but I couldn't find the way I implemented it, this version needs closure, php>=5.3, but could be altered not to:

$customer['address'] = '123 fake st';
$customer['name'] = 'Tim';
$customer['dob'] = '12/08/1986';
$customer['dontSortMe'] = 'this value doesnt need to be sorted';

$order = array('name', 'dob', 'address');

$keys= array_flip($order);
uksort($customer, function($a, $b)use($keys){
    return $keys[$a] - $keys[$b];
});
print_r($customer);

Of course 'dontSortMe' needs to be sorted out, and may appear first in the example

Answer 3

I used the Darkwaltz4's solution but used array_fill_keys instead of array_flip, to fill with NULL if a key is not set in $array.

$properOrderedArray = array_replace(array_fill_keys($keys, null), $array);