I\'m trying to execute a Java program from the command line in Windows. Here is my code:
import java.io.File;
import java.io.FileInputStream;
import java.io.
You can compile any java source using javac in command line ; eg, javac CopyFile.java. To run : java CopyFile. You can also compile all java files using javac *.java as long as they're in the same directory
If you're having an issue resulting with "could not find or load main class" you may not have jre in your path. Have a look at this question: Could not find or load main class
As of Java 9, the JDK includes jshell
, a Java REPL.
Assuming the JDK 9+ bin
directory is correctly added to your path, you will be able to simply:
jshell File.java
— File.java
being your file of course. main
method: jshell> File.main(null)
./exit
Full documentation for JShell can be found here.
On Windows 7 I had to do the following:
quick way
long way
This likely breaks when you upgrade your JDK installation but you have access to all the command line tools now.
Follow comments above about how to compile the file ("javac MyFile.java" then "java MyFile") https://stackoverflow.com/a/33149828/194872
In case your Java class is in some package. Suppose your Java class named ABC.java
is present in com.hello.programs
, then you need to run it with the package name.
Compile it in the usual way:
C:\SimpleJavaProject\src\com\hello\programs > javac ABC.java
But to run it, you need to give the package name and then your java class name:
C:\SimpleJavaProject\src > java com.hello.programs.ABC
Complile a Java file to generate a class:
javac filename.java
Execute the generated class:
java filename
Assuming the file is called "CopyFile.java", do the following:
javac CopyFile.java
java -cp . CopyFile
The first line compiles the source code into executable byte code. The second line executes it, first adding the current directory to the class path (just in case).