I have the following in my gulpfile.js:
var sass_paths = [
\'./httpdocs-site1/media/sass/**/*.scss\',
\'./httpdocs-site2/media/sass/**/*
Using gulp-if
helps me a lot.
The gulp-if first argument. is the gulp-match second argument condition
gulp-if can be found in gulp-if
import {task, src, dest} from 'gulp';
import VinylFile = require("vinyl");
const gulpif = require('gulp-if');
src(['foo/*/**/*.md', 'bar/*.md'])
.pipe(gulpif((file: VinylFile) => /foo\/$/.test(file.base), dest('dist/docs/overview')))
.pipe(gulpif((file: VinylFile) => /bar\/$/.test(file.base), dest('dist/docs/guides')))
});
I guess that the running tasks per folder recipe may help.
Update
Following the ideas in the recipe, and oversimplifying your sample just to give the idea, this can be a solution:
var gulp = require('gulp'),
path = require('path'),
merge = require('merge-stream');
var folders = ['httpdocs-site1', 'httpdocs-site2', 'httpdocs-site3'];
gulp.task('default', function(){
var tasks = folders.map(function(element){
return gulp.src(element + '/media/sass/**/*.scss', {base: element + '/media/sass'})
// ... other steps ...
.pipe(gulp.dest(element + '/media/css'));
});
return merge(tasks);
});
The destination will have the same directory structure as the source.