Type.GetType(“namespace.a.b.ClassName”) returns null

Question

This code:

Type.GetType(\"namespace.a.b.ClassName\")

returns null.

and I have in the usings:

using nam         


        

Answer 1

Make sure that the comma is directly after the fully qualified name

typeof(namespace.a.b.ClassName, AssemblyName)

As this wont work

typeof(namespace.a.b.ClassName ,AssemblyName)

I was stumped for a few days on this one

Answer 2

For me, a "+" was the key! This is my class(it is a nested one) :

namespace PortalServices
{
public class PortalManagement : WebService
{
    public class Merchant
    {}
}
}

and this line of code worked:

Type type = Type.GetType("PortalServices.PortalManagement+Merchant");

Answer 3

if your class is not in current assambly you must give qualifiedName and this code shows how to get qualifiedname of class

string qualifiedName = typeof(YourClass).AssemblyQualifiedName;

and then you can get type with qualifiedName

Type elementType = Type.GetType(qualifiedName);

Answer 4

This solution above seems to be the best to me, but it didn't work for me, so I did it as follows:

AssemblyName assemblyName = AssemblyName.GetAssemblyName(HttpContext.Current.Server.MapPath("~\\Bin\\AnotherAssembly.dll"));
string typeAssemblyQualifiedName = string.Join(", ", "MyNamespace.MyType", assemblyName.FullName);

Type myType = Type.GetType(typeAssemblyQualifiedName);

The precondition is that you know the path of the assembly. In my case I know it because this is an assembly built from another internal project and its included in our project's bin folder.

In case it matters I am using Visual Studio 2013, my target .NET is 4.0. This is an ASP.NET project, so I am getting absolute path via HttpContext. However, absolute path is not a requirement as it seems from MSDN on AssemblyQualifiedNames

Answer 5

If the assembly is referenced and the Class visible :

typeof(namespace.a.b.ClassName)

GetType returns null because the type is not found, with typeof, the compiler may help you to find out the error.

Answer 6

You can also get the type without assembly qualified name but with the dll name also, for example:

Type myClassType = Type.GetType("TypeName,DllName");

I had the same situation and it worked for me. I needed an object of type "DataModel.QueueObject" and had a reference to "DataModel" so I got the type as follows:

Type type = Type.GetType("DataModel.QueueObject,DataModel");

The second string after the comma is the reference name (dll name).