I have this code
$vad = 1.1;
print gettype($vad);
var_dump($vad);
this will output:
double
float(1.1)
For PHP, they are the same. http://www.php.net/manual/en/language.types.float.php :
Floating point numbers (also known as "floats", "doubles", or "real numbers") can be specified using any of the following syntaxes: [...]
The confusing part is why gettype (which you shouldn't use, anyway) returns "double" instead of "float". The answer is http://de2.php.net/manual/en/function.gettype.php:
" double " (for historical reasons "double" is returned in case of a float , and not simply "float")
As of PHP 7.0.6 on Windows, comparing this command without xdebug:
$ php -r 'var_dump(28.4);'
float(28.4)
and with xdebug:
$ php -r 'var_dump(28.4);'
Command line code:1:
double(28.4)
Note that this only changes var_dump() output, but not the actual memory management.
This may address some concerns why you see double
instead of float
shown in var_dump in some other machines.
Also, with or without xdebug, gettype
still returns string(6) "double"
.
There is no difference in PHP. float
, double
or real
are the same datatype.
At the C level, everything is stored as a double
.
The real size is still platform-dependent.
See the manual for more details:
http://www.php.net/manual/en/language.types.float.php
In PHP 7.0.14
function test(double $a) {
var_dump($a);
}
test(2.2111);
Returns "Fatal error: Uncaught TypeError: Argument 1 passed to test() must be an instance of double, float given".
function test(float $a) {
var_dump($a);
}
test(2.2111);
Prints 2.2111 to the screen.