Easy way to test if each element in an numpy array lies between two values?

Question

I was wondering if there was a syntactically simple way of checking if each element in a numpy array lies between two numbers.

In other words, just as numpy.ar

Answer 1

You can also center the matrix and use the distance to 0

upper_limit = 5
lower_limit = 1
a = np.array([1,2,3,4,5])
your_mask = np.abs(a- 0.5*(upper_limit+lower_limit))<0.5*(upper_limit-lower_limit)

One thing to keep in mind is that the comparison will be symmetric on both sides, so it can do 1<x<5 or 1<=x<=5, but not 1<=x<5

Answer 2

one solution would be:

a = numpy.array([1,2,3,4,5])
(a > 1).all() and (a < 5).all()

if you want the acutal array of truth vaues, just use:

(a > 1) & (a < 5)

Answer 3

Another would be to use numpy.any, Here is an example

import numpy as np
a = np.array([1,2,3,4,5])
np.any((a < 1)|(a > 5 ))