Hide Command Window of .BAT file that Executes Another .EXE File

Question

This is a batch file in Windows.

Here is my .bat file

@echo off
copy \"C:\\Remoting.config-Training\" \"C:\\Remoting.config\"

\"C:\\ThirdPar         


        

Answer 1

I used this to start a cmd file from C#:

Process proc = new Process();
proc.StartInfo.WorkingDirectory = "myWorkingDirectory";
proc.StartInfo.FileName = "myFileName.cmd";
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
proc.Start();
proc.WaitForExit();

Answer 2

You might be interested in trying my silentbatch program, which will run a .bat/.cmd script, suppress creation of the Command Prompt window entirely (so you won't see it appear and then disappear), and optionally log the output to a specified file.

Answer 3

To make the command window of a .bat file that executes a .exe file exit out as fast as possible, use the line @start before the file you're trying to execute. Here is an example:

(insert other code here)
@start executable.exe
(insert other code here)

You don't have to use other code with @start executable.exe.

Answer 4

Great tip. It works with batch files that are running a java program also.

start javaw -classpath "%CP%" main.Main

Answer 5

Create a .vbs file with this code:

CreateObject("Wscript.Shell").Run "your_batch.bat",0,True

This .vbs will run your_batch.bat hidden.

Works fine for me.

Answer 6

Using start works fine, unless you are using a scripting language. Fortunately, there's a way out for Python - just use pythonw.exe instead of python.exe:

:: Title not needed:
start pythonw.exe application.py

In case you need quotes, do this:

:: Title needed
start "Great Python App" pythonw.exe "C:\Program Files\Vendor\App\application.py"