I thought this would be really simple but it\'s presenting some difficulties. If I have
std::string name = \"John\";
int age = 21;
How do I
You can concatenate int to string by using the given below simple trick, but note that this only works when integer is of single digit. Otherwise, add integer digit by digit to that string.
string name = "John";
int age = 5;
char temp = 5 + '0';
name = name + temp;
cout << name << endl;
Output: John5
If you'd like to use +
for concatenation of anything which has an output operator, you can provide a template version of operator+
:
template <typename L, typename R> std::string operator+(L left, R right) {
std::ostringstream os;
os << left << right;
return os.str();
}
Then you can write your concatenations in a straightforward way:
std::string foo("the answer is ");
int i = 42;
std::string bar(foo + i);
std::cout << bar << std::endl;
Output:
the answer is 42
This isn't the most efficient way, but you don't need the most efficient way unless you're doing a lot of concatenation inside a loop.
As a Qt-related question was closed in favour of this one, here's how to do it using Qt:
QString string = QString("Some string %1 with an int somewhere").arg(someIntVariable);
string.append(someOtherIntVariable);
The string variable now has someIntVariable's value in place of %1 and someOtherIntVariable's value at the end.
#include <sstream>
template <class T>
inline std::string to_string (const T& t)
{
std::stringstream ss;
ss << t;
return ss.str();
}
Then your usage would look something like this
std::string szName = "John";
int numAge = 23;
szName += to_string<int>(numAge);
cout << szName << endl;
Googled [and tested :p ]
The std::ostringstream is a good method, but sometimes this additional trick might get handy transforming the formatting to a one-liner:
#include <sstream>
#define MAKE_STRING(tokens) /****************/ \
static_cast<std::ostringstream&>( \
std::ostringstream().flush() << tokens \
).str() \
/**/
Now you can format strings like this:
int main() {
int i = 123;
std::string message = MAKE_STRING("i = " << i);
std::cout << message << std::endl; // prints: "i = 123"
}
In alphabetical order:
std::string name = "John";
int age = 21;
std::string result;
// 1. with Boost
result = name + boost::lexical_cast<std::string>(age);
// 2. with C++11
result = name + std::to_string(age);
// 3. with FastFormat.Format
fastformat::fmt(result, "{0}{1}", name, age);
// 4. with FastFormat.Write
fastformat::write(result, name, age);
// 5. with the {fmt} library
result = fmt::format("{}{}", name, age);
// 6. with IOStreams
std::stringstream sstm;
sstm << name << age;
result = sstm.str();
// 7. with itoa
char numstr[21]; // enough to hold all numbers up to 64-bits
result = name + itoa(age, numstr, 10);
// 8. with sprintf
char numstr[21]; // enough to hold all numbers up to 64-bits
sprintf(numstr, "%d", age);
result = name + numstr;
// 9. with STLSoft's integer_to_string
char numstr[21]; // enough to hold all numbers up to 64-bits
result = name + stlsoft::integer_to_string(numstr, 21, age);
// 10. with STLSoft's winstl::int_to_string()
result = name + winstl::int_to_string(age);
// 11. With Poco NumberFormatter
result = name + Poco::NumberFormatter().format(age);
#include <string>
)#include <sstream>
(from standard C++)