Scala - modifying nested elements in xml

Question

I\'m learning scala, and I\'m looking to update a nested node in some xml. I\'ve got something working but i\'m wondering if its the most elegant way.

I have some xm

Answer 1

All this time, and no one actually gave the most appropriate answer! Now that I have learned of it, though, here's my new take on it:

import scala.xml._
import scala.xml.transform._

object t1 extends RewriteRule {
  override def transform(n: Node): Seq[Node] = n match {
    case Elem(prefix, "version", attribs, scope, _*)  =>
      Elem(prefix, "version", attribs, scope, Text("2"))
    case other => other
  }
}

object rt1 extends RuleTransformer(t1)

object t2 extends RewriteRule {
  override def transform(n: Node): Seq[Node] = n match {
    case sn @ Elem(_, "subnode", _, _, _*) => rt1(sn)
    case other => other
  }
}

object rt2 extends RuleTransformer(t2)

rt2(InputXml)

Now, for a few explanations. The class RewriteRule is abstract. It defines two methods, both called transform. One of them takes a single Node, the other a Sequence of Node. It's an abstract class, so we can't instantiate it directly. By adding a definition, in this case override one of the transformmethods, we are creating an anonymous subclass of it. Each RewriteRule needs concern itself with a single task, though it can do many.

Next, class RuleTransformer takes as parameters a variable number of RewriteRule. It's transform method takes a Node and return a Sequence of Node, by applying each and every RewriteRule used to instantiate it.

Both classes derive from BasicTransformer, which defines a few methods with which one need not concern oneself at a higher level. It's apply method calls transform, though, so both RuleTransformer and RewriteRule can use the syntactic sugar associated with it. In the example, the former does and the later does not.

Here we use two levels of RuleTransformer, as the first applies a filter to higher level nodes, and the second apply the change to whatever passes the filter.

The extractor Elem is also used, so that there is no need to concern oneself with details such as namespace or whether there are attributes or not. Not that the content of the element version is completely discarded and replaced with 2. It can be matched against too, if needed.

Note also that the last parameter of the extractor is _*, and not _. That means these elements can have multiple children. If you forget the *, the match may fail. In the example, the match would not fail if there were no whitespaces. Because whitespaces are translated into Text elements, a single whitespace under subnode would case the match to fail.

This code is bigger than the other suggestions presented, but it has the advantage of having much less knowledge of the structure of the XML than the others. It changes any element called version that is below -- no matter how many levels -- an element called subnode, no matter namespaces, attributes, etc.

Furthermore... well, if you have many transformations to do, recursive pattern matching becomes quickly unyielding. Using RewriteRule and RuleTransformer, you can effectively replace xslt files with Scala code.