How to change a command line argument in Bash?

Question

Is there a way to change the command line arguments in a Bash script? For example, a Bash script is invoked like this:

./foo arg1 arg2  

Is t

Answer 1

Optimising for legibility and maintainability, you may be better off assigning $1 and $2 to more meaningful variables (I don't know, input_filename = $1 and output_filename = $2 or something) and then overwriting one of those variables (input_filename = 'chintz'), leaving the input to the script unchanged, in case it is needed elsewhere.

Answer 2

You have to reset all arguments. To change e.g. $3:

$ set -- "${@:1:2}" "new" "${@:4}"

Basically you set all arguments to their current values, except for the one(s) that you want to change. set -- is also specified by POSIX 7.

The "${@:1:2}" notation is expanded to the two (hence the 2 in the notation) positional arguments starting from offset 1 (i.e. $1). It is a shorthand for "$1" "$2" in this case, but it is much more useful when you want to replace e.g. "${17}".

Answer 3

I know this is an old one but I found the answer by thkala very helpful, so I have used the idea and expanded on it slightly to enable me to add defaults for any argument which has not been defined - for example:

    # set defaults for the passed arguments (if any) if not defined.
    #
    arg1=${1:-"default-for-arg-1"}
    arg2=${2:-"default-for-arg-2"}
    set -- "${arg1}" "${arg2}"
    unset arg1 arg2

I hope this is of use to someone else.