Django ChoiceField

Question

I\'m trying to solve following issue:

I have a web page that can see only moderators. Fields displayed on this page (after user have registered):
Username, Firs

Answer 1

Better Way to Provide Choice inside a django Model :

from django.db import models

class Student(models.Model):
    FRESHMAN = 'FR'
    SOPHOMORE = 'SO'
    JUNIOR = 'JR'
    SENIOR = 'SR'
    GRADUATE = 'GR'
    YEAR_IN_SCHOOL_CHOICES = [
        (FRESHMAN, 'Freshman'),
        (SOPHOMORE, 'Sophomore'),
        (JUNIOR, 'Junior'),
        (SENIOR, 'Senior'),
        (GRADUATE, 'Graduate'),
    ]
    year_in_school = models.CharField(
        max_length=2,
        choices=YEAR_IN_SCHOOL_CHOICES,
        default=FRESHMAN,
    )

Answer 2

New method in Django 3

you can use Field.choices Enumeration Types new update in django3 like this :

from django.db import models

class Status(models.TextChoices):
    UNPUBLISHED = 'UN', 'Unpublished'
    PUBLISHED = 'PB', 'Published'


class Book(models.Model):
    status = models.CharField(
        max_length=2,
        choices=Status.choices,
        default=Status.UNPUBLISHED,
    )

django docs

Answer 3

If your choices are not pre-decided or they are coming from some other source, you can generate them in your view and pass it to the form .

Example:

views.py:

def my_view(request, interview_pk):
    interview = Interview.objects.get(pk=interview_pk)
    all_rounds = interview.round_set.order_by('created_at')
    all_round_names = [rnd.name for rnd in all_rounds]
    form = forms.AddRatingForRound(all_round_names)
    return render(request, 'add_rating.html', {'form': form, 'interview': interview, 'rounds': all_rounds})

forms.py

class AddRatingForRound(forms.ModelForm):

    def __init__(self, round_list, *args, **kwargs):
        super(AddRatingForRound, self).__init__(*args, **kwargs)
        self.fields['name'] = forms.ChoiceField(choices=tuple([(name, name) for name in round_list]))

    class Meta:
        model = models.RatingSheet
        fields = ('name', )

template:

<form method="post">
    {% csrf_token %}
    {% if interview %}
         {{ interview }}
    {% endif %}
    {% if rounds %}
    <hr>
        {{ form.as_p }}
        <input type="submit" value="Submit" />
    {% else %}
        <h3>No rounds found</h3>
    {% endif %}

</form>

Answer 4

First I recommend you as @ChrisHuang-Leaver suggested to define a new file with all the choices you need it there, like choices.py:

STATUS_CHOICES = (
    (1, _("Not relevant")),
    (2, _("Review")),
    (3, _("Maybe relevant")),
    (4, _("Relevant")),
    (5, _("Leading candidate"))
)
RELEVANCE_CHOICES = (
    (1, _("Unread")),
    (2, _("Read"))
)

Now you need to import them on the models, so the code is easy to understand like this(models.py):

from myApp.choices import * 

class Profile(models.Model):
    user = models.OneToOneField(User)    
    status = models.IntegerField(choices=STATUS_CHOICES, default=1)   
    relevance = models.IntegerField(choices=RELEVANCE_CHOICES, default=1)

And you have to import the choices in the forms.py too:

forms.py:

from myApp.choices import * 

class CViewerForm(forms.Form):

    status = forms.ChoiceField(choices = STATUS_CHOICES, label="", initial='', widget=forms.Select(), required=True)
    relevance = forms.ChoiceField(choices = RELEVANCE_CHOICES, required=True)

Anyway you have an issue with your template, because you're not using any {{form.field}}, you generate a table but there is no inputs only hidden_fields.

When the user is staff you should generate as many input fields as users you can manage. I think django form is not the best solution for your situation.

I think it will be better for you to use html form, so you can generate as many inputs using the boucle: {% for user in users_list %} and you generate input with an ID related to the user, and you can manage all of them in the view.