Been looking around on here for a while but can\'t seem to find a working solution.
I\'m trying to disable the swipe to go back to previous view gesture, in Swift.
RowanPD's logic for Swift 4
private var popGesture: UIGestureRecognizer?
override func viewDidAppear(_ animated: Bool) {
super.viewDidAppear(animated)
if navigationController!.responds(to: #selector(getter: UINavigationController.interactivePopGestureRecognizer)) {
self.popGesture = navigationController!.interactivePopGestureRecognizer
self.navigationController!.view.removeGestureRecognizer(navigationController!.interactivePopGestureRecognizer!)
}
}
override func viewWillDisappear(_ animated: Bool) {
super.viewWillDisappear(animated)
if let gesture = self.popGesture {
self.navigationController!.view.addGestureRecognizer(gesture)
}
}
If requirement is to show side menu on some of the screens then add AddScreenEdgePanGesture on this specific view instead of navigationController view
replace it
SideMenuManager.default.menuAddScreenEdgePanGesturesToPresent(toView: self.navigationController?.view)
with this
SideMenuManager.default.menuAddScreenEdgePanGesturesToPresent(toView: self.view)
This is something you missed if it doesn't work after you tried all.
navigationController?.interactivePopGestureRecognizer?.isEnabled = false
to your viewWillAppear(animated:) method. UINavigationControllerDelegate
, UIGestureRecognizerDelegate
protocols. if so, just remove it.I was able to do this by returning false in gestureRecognizerShouldBegin
class ViewController2: UIViewController, UIGestureRecognizerDelegate {
...
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
self.navigationController?.interactivePopGestureRecognizer.delegate = self
}
func gestureRecognizerShouldBegin(gestureRecognizer: UIGestureRecognizer) -> Bool {
return false
}