How to get the separate digits of an int number?

Question

I have numbers like 1100, 1002, 1022 etc. I would like to have the individual digits, for example for the first number 1100 I want to have 1, 1, 0, 0.

How can I get

Answer 1

public int[] getDigitsOfANumber(int number) {
    String numStr = String.valueOf(number);
    int retArr[] = new int[numStr.length()];

    for (int i = 0; i < numStr.length(); i++) {
        char c = numStr.charAt(i);
        int digit = c;
        int zero = (char) '0';
        retArr[i] = digit - zero;

    }
    return retArr;
}

Answer 2

I haven't seen anybody use this method, but it worked for me and is short and sweet:

int num = 5542;
String number = String.valueOf(num);
for(int i = 0; i < number.length(); i++) {
    int j = Character.digit(number.charAt(i), 10);
    System.out.println("digit: " + j);
}

This will output:

digit: 5
digit: 5
digit: 4
digit: 2

Answer 3

Here is my answer, I did it for myself and I hope it's simple enough for those who don't want to use the String approach or need a more math-y solution:

public static void reverseNumber2(int number) {

    int residual=0;
    residual=number%10;
    System.out.println(residual);

    while (residual!=number)  {
          number=(number-residual)/10;
          residual=number%10;
          System.out.println(residual);
    }
}

So I just get the units, print them out, substract them from the number, then divide that number by 10 - which is always without any floating stuff, since units are gone, repeat.

Answer 4

neither chars() nor codePoints() — the other lambda

String number = Integer.toString( 1100 );

IntStream.range( 0, number.length() ).map( i -> Character.digit( number.codePointAt( i ), 10 ) ).toArray();  // [1, 1, 0, 0]

Answer 5

Easier way I think is to convert the number to string and use substring to extract and then convert to integer.

Something like this:

int digits1 =Integer.parseInt( String.valueOf(201432014).substring(0,4));
    System.out.println("digits are: "+digits1);

ouput is 2014

Answer 6

Java 8 solution to get digits as int[] from an integer that you have as a String:

int[] digits = intAsString.chars().map(i -> i - '0').toArray();