I\'m trying to write a function that converts numbers to roman numerals. This is my code so far; however, it only works with numbers that are less than 400. Is there a quick
The solution is lengthy, but easy to understand for a beginner. Process up to 3000
namespace RomansTranslator
{
using System;
using System.Collections.Generic;
/// <summary>
/// Accepts a number (between 1 and 3000) and prints its Roman equivalent.
/// </summary>
class Program
{
static void Main(string[] args)
{
string number = string.Empty;
Console.Write("Enter the Numeric number : ");
number = Console.ReadLine();
if (IsValid(number)) // Validates the input
{
string roman = ConvertToRoman(number);
Console.WriteLine("Roman Number is " + roman);
}
else
{
Console.WriteLine("Invalid Number");
}
Console.ReadKey();
}
private static string ConvertToRoman(string numberString)
{
string romanValue = string.Empty;
int number = Convert.ToInt32(numberString);
if (number >= 1)
{
// Loop through each roman character from highest
foreach (int item in RomanDictionary().Keys)
{
while (number >= item)
{
romanValue = romanValue + RomanString(item);
number -= item;
}
}
}
return romanValue;
}
/// <summary>
/// Returns Roman Equvalent
/// </summary>
/// <param name="n"></param>
/// <returns></returns>
private static string RomanString(int n)
{
string romanString = string.Empty;
romanString = RomanDictionary()[n].ToString();
return romanString;
}
/// <summary>
/// List of Roman Characters
/// </summary>
/// <returns></returns>
private static Dictionary<int, string> RomanDictionary()
{
Dictionary<int, string> romanDic = new Dictionary<int, string>();
romanDic.Add(1000, "M");
romanDic.Add(900, "CM");
romanDic.Add(500, "D");
romanDic.Add(400, "CD");
romanDic.Add(100, "C");
romanDic.Add(90, "XC");
romanDic.Add(50, "L");
romanDic.Add(40, "XL");
romanDic.Add(10, "X");
romanDic.Add(9, "IX");
romanDic.Add(5, "V");
romanDic.Add(4, "IV");
romanDic.Add(1, "I");
return romanDic;
}
/// <summary>
/// Validates the Input
/// </summary>
/// <param name="input"></param>
/// <returns></returns>
private static bool IsValid(string input)
{
int value = 0;
bool isValid = false;
if (int.TryParse(input, out value))
{
if (value <= 3000)
{
isValid = true;
}
}
return isValid;
}
}
}
Here is a slim solution from DotNetSnippets
private string ToRomanNumber(int number)
{
StringBuilder result = new StringBuilder();
int[] digitsValues = { 1, 4, 5, 9, 10, 40, 50, 90, 100, 400, 500, 900, 1000 };
string[] romanDigits = { "I", "IV", "V", "IX", "X", "XL", "L", "XC", "C", "CD", "D", "CM", "M" };
while (number > 0)
{
for (int i = digitsValues.Count() - 1; i >= 0; i--)
if (number / digitsValues[i] >= 1)
{
number -= digitsValues[i];
result.Append(romanDigits[i]);
break;
}
}
return result.ToString();
}
I can provide a method which is comparatively simpler than the existing
using Microsoft.VisualBasic;
using System;
using System.Collections;
using System.Collections.Generic;
using System.Data;
using System.Diagnostics;
public class Form1
{
int[] indx = {
1,
2,
3,
4,
5,
10,
50,
100,
500,
1000
// initialize array of integers
};
string[] row = {
"I",
"II",
"III",
"IV",
"V",
"X",
"L",
"C",
"D",
"M"
//Carasponding roman letters in for the numbers in the array
};
// integer to indicate the position index for link two arrays
int limit = 9;
//string to store output
string output = "";
private void Button1_Click(System.Object sender, System.EventArgs e)
{
int num = 0;
// stores the input
output = "";
// clear output before processing
num = Convert.ToInt32(txt1.Text);
// get integer value from the textbox
//Loop until the value became 0
while (num > 0) {
num = find(num);
//call function for processing
}
txt2.Text = output;
// display the output in text2
}
public int find(int Num)
{
int i = 0;
// loop variable initialized with 0
//Loop until the indx(i).value greater than or equal to num
while (indx(i) <= Num) {
i += 1;
}
// detemine the value of limit depends on the itetration
if (i != 0) {
limit = i - 1;
} else {
limit = 0;
}
output = output + row(limit);
//row(limit) is appended with the output
Num = Num - indx(limit);
// calculate next num value
return Num;
//return num value for next itetration
}
}
@Backwards_Dave You wanted a solution that goes to max number, here you go:
public class ConvertDecimalNumberToRomanNumberType
{
public class RomanNumberType
{
public string RomanNumber;
public int RomanNumberValue;
}
public List<RomanNumberType> RomanNumbers;
public void Initialize()
{
RomanNumbers = new List<RomanNumberType>();
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "M", RomanNumberValue = 1000 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "CM", RomanNumberValue = 900 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "D", RomanNumberValue = 500 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "CD", RomanNumberValue = 400 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "C", RomanNumberValue = 100 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "XC", RomanNumberValue = 90 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "L", RomanNumberValue = 50 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "XL", RomanNumberValue = 40 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "X", RomanNumberValue = 10 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "IX", RomanNumberValue = 9 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "V", RomanNumberValue = 5 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "IV", RomanNumberValue = 4 });
RomanNumbers.Add(new RomanNumberType() { RomanNumber = "I", RomanNumberValue = 1 });
}
public string ConvertDecimalNumberToRomanNumber(int GetConvertDecimalNumberToRomanNumber)
{
string
FunctionResult
, CurrentRomanNumber = "";
int
FunctionGet = GetConvertDecimalNumberToRomanNumber
, DecimalNumberRemaining = FunctionGet;
foreach(RomanNumberType RomanNumber in RomanNumbers)
while(RomanNumber.RomanNumberValue <= DecimalNumberRemaining)
{
DecimalNumberRemaining -= RomanNumber.RomanNumberValue;
CurrentRomanNumber += RomanNumber.RomanNumber;
}
FunctionResult = CurrentRomanNumber;
return FunctionResult;
}
}
usage :
ConvertDecimalNumberToRomanNumberType ConvertDecimalNumberToRomanNumberObject = new ConvertDecimalNumberToRomanNumberType();
ConvertDecimalNumberToRomanNumberObject.Initialize();
var SomeVariable = ConvertDecimalNumberToRomanNumberObject.ConvertDecimalNumberToRomanNumber(1999);
Here's a much simpler algorithm - forgive me, I don't know C# so I'm writing this in JavaScript, but the same algorithm should apply (and I've commented so you can understand the algorithm):
function intToRoman(int) {
// create 2-dimensional array, each inner array containing
// roman numeral representations of 1-9 in each respective
// place (ones, tens, hundreds, etc...currently this handles
// integers from 1-3999, but could be easily extended)
var romanNumerals = [
['', 'i', 'ii', 'iii', 'iv', 'v', 'vi', 'vii', 'viii', 'ix'], // ones
['', 'x', 'xx', 'xxx', 'xl', 'l', 'lx', 'lxx', 'lxxx', 'xc'], // tens
['', 'c', 'cc', 'ccc', 'cd', 'd', 'dc', 'dcc', 'dccc', 'cm'], // hundreds
['', 'm', 'mm', 'mmm'] // thousands
];
// split integer string into array and reverse array
var intArr = int.toString().split('').reverse(),
len = intArr.length,
romanNumeral = '',
i = len;
// starting with the highest place (for 3046, it would be the thousands
// place, or 3), get the roman numeral representation for that place
// and append it to the final roman numeral string
while (i--) {
romanNumeral += romanNumerals[ i ][ intArr[i] ];
}
return romanNumeral;
}
console.log( intToRoman(3046) ); // outputs mmmxlvi
This should be the simplest solution.
public string IntToRoman(int num)
{
var result = string.Empty;
var map = new Dictionary<string, int>
{
{"M", 1000 },
{"CM", 900},
{"D", 500},
{"CD", 400},
{"C", 100},
{"XC", 90},
{"L", 50},
{"XL", 40},
{"X", 10},
{"IX", 9},
{"V", 5},
{"IV", 4},
{"I", 1}
};
foreach (var pair in map)
{
result += string.Join(string.Empty, Enumerable.Repeat(pair.Key, num / pair.Value));
num %= pair.Value;
}
return result;
}