Rails 4 LIKE query - ActiveRecord adds quotes

Question

I am trying to do a like query like so

def self.search(search, page = 1 )
  paginate :per_page => 5, :page =>          


        

Answer 1

Instead of using the conditions syntax from Rails 2, use Rails 4's where method instead:

def self.search(search, page = 1 )
  wildcard_search = "%#{search}%"

  where("name ILIKE :search OR postal_code LIKE :search", search: wildcard_search)
    .page(page)
    .per_page(5)
end

NOTE: the above uses parameter syntax instead of ? placeholder: these both should generate the same sql.

def self.search(search, page = 1 )
  wildcard_search = "%#{search}%"

  where("name ILIKE ? OR postal_code LIKE ?", wildcard_search, wildcard_search)
    .page(page)
    .per_page(5)
end

NOTE: using ILIKE for the name - postgres case insensitive version of LIKE

Answer 2

While string interpolation will work, as your question specifies rails 4, you could be using Arel for this and keeping your app database agnostic.

def self.search(query, page=1)
  query = "%#{query}%"
  name_match = arel_table[:name].matches(query)
  postal_match = arel_table[:postal_code].matches(query)
  where(name_match.or(postal_match)).page(page).per_page(5)
end

Answer 3

If someone is using column names like "key" or "value", then you still see the same error that your mysql query syntax is bad. This should fix:

.where("`key` LIKE ?", "%#{key}%")

Answer 4

Try

 def self.search(search, page = 1 )
    paginate :per_page => 5, :page => page,
      :conditions => ["name LIKE  ? OR postal_code like ?", "%#{search}%","%#{search}%"],   order => 'name'
  end

See the docs on AREL conditions for more info.

Answer 5

Your placeholder is replaced by a string and you're not handling it right.

Replace

"name LIKE '%?%' OR postal_code LIKE '%?%'", search, search

with

"name LIKE ? OR postal_code LIKE ?", "%#{search}%", "%#{search}%"

Answer 6

.find(:all, where: "value LIKE product_%", params: { limit: 20, page: 1 })