How to get path to the current vimscript being executed

Question

In my vim plugin, I have two files:

myplugin/plugin.vim
myplugin/plugin_helpers.py

I would like to import plugin_helpers from plugin.vim (u

Answer 1

" Relative path of script file:
let s:path = expand('<sfile>')

" Absolute path of script file:
let s:path = expand('<sfile>:p')

" Absolute path of script file with symbolic links resolved:
let s:path = resolve(expand('<sfile>:p'))

" Folder in which script resides: (not safe for symlinks)
let s:path = expand('<sfile>:p:h')

" If you're using a symlink to your script, but your resources are in
" the same directory as the actual script, you'll need to do this:
"   1: Get the absolute path of the script
"   2: Resolve all symbolic links
"   3: Get the folder of the resolved absolute file
let s:path = fnamemodify(resolve(expand('<sfile>:p')), ':h')

I use that last one often because my ~/.vimrc is a symbolic link to a script in a git repository.

Answer 2

Found it:

let s:current_file=expand("<sfile>")

Answer 3

It is worth mentioning that the above solution will only work outside of a function.

This will not give the desired result:

function! MyFunction()
let s:current_file=expand('<sfile>:p:h')
echom s:current_file
endfunction

But this will:

let s:current_file=expand('<sfile>')
function! MyFunction()
echom s:current_file
endfunction

Here's a full solution to OP's original question:

let s:path = expand('<sfile>:p:h')

function! MyPythonFunction()
import sys
import os
script_path = vim.eval('s:path')

lib_path = os.path.join(script_path, '.') 
sys.path.insert(0, lib_path)                                       

import vim
import plugin_helpers
plugin_helpers.do_some_cool_stuff_here()
vim.command("badd %(result)s" % {'result':plugin_helpers.get_result()})

EOF
endfunction