How to get everything after last slash in a URL?

Question

How can I extract whatever follows the last slash in a URL in Python? For example, these URLs should return the following:

URL: http://www.test.com/TEST1
ret         


        

Answer 1

Use urlparse to get just the path and then split the path you get from it on / characters:

from urllib.parse import urlparse

my_url = "http://example.com/some/path/last?somequery=param"
last_path_fragment = urlparse(my_url).path.split('/')[-1]  # returns 'last'

Note: if your url ends with a / character, the above will return '' (i.e. the empty string). If you want to handle that case differently, you need to strip the trailing / character before you split the path:

my_url = "http://example.com/last/"
# handle URL ending in `/` by removing it.
last_path_fragment = urlparse(my_url).path.rstrip('/').split('/')[-1]  # returns 'last'

Answer 2

Split the url and pop the last element url.split('/').pop()

Answer 3

You don't need fancy things, just see the string methods in the standard library and you can easily split your url between 'filename' part and the rest:

url.rsplit('/', 1)

So you can get the part you're interested in simply with:

url.rsplit('/', 1)[-1]

Answer 4

url ='http://www.test.com/page/TEST2'.split('/')[4]
print url

Output: TEST2.

Answer 5

extracted_url = url[url.rfind("/")+1:];

Answer 6

First extract the path element from the URL:

from urllib.parse import urlparse
parsed= urlparse('https://www.dummy.example/this/is/PATH?q=/a/b&r=5#asx')

and then you can extract the last segment with string functions:

parsed.path.rpartition('/')[2]

(example resulting to 'PATH')