Google App Engine and 404 error

Question

I\'ve setup a static website on GAE using hints found elsewhere, but can\'t figure out how to return a 404 error. My app.yaml file looks like

- url: (.*)/
           


        

Answer 1

You can create a function to handle your errors for any of the status codes. You're case being 404, define a function like this:

def Handle404(request, response, exception):
     response.out.write("Your error message") 
     response.set_status(404)`

You can pass anything - HTML / plain-text / templates in the response.out.write function. Now, add the following declaration after your app declaration.

app.error_handlers[404] = Handle404

This worked for me.

Answer 2

You need to register a catch-all script handler. Append this at the end of your app.yaml:

- url: /.*
  script: main.py

In main.py you will need to put this code:

from google.appengine.ext import webapp
from google.appengine.ext.webapp.util import run_wsgi_app

class NotFoundPageHandler(webapp.RequestHandler):
    def get(self):
        self.error(404)
        self.response.out.write('<Your 404 error html page>')

application = webapp.WSGIApplication([('/.*', NotFoundPageHandler)],
                                     debug=True)

def main():
    run_wsgi_app(application)

if __name__ == "__main__":
    main()

Replace <Your 404 error html page> with something meaningful. Or better use a template, you can read how to do that here.

Please let me know if you have problems setting this up.

Answer 3

google app engine now has Custom Error Responses

so you can now add an error_handlers section to your app.yaml, as in this example:

error_handlers:

- file: default_error.html

- error_code: over_quota
    file: over_quota.html