Finding context-free grammar (CFG) for L = { a^i b^j c^k | i > j + k }, i, j, k > 0

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情歌与酒
情歌与酒 2020-12-02 06:46

My response:

S --> aABbCc

B --> AbB | a

C --> BcC | λ

A --> aD

D --> λ

am I missing something here?

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