Dial a phone number with an access code programmatically in iOS

Question

How can I dial a phone number that includes a number and access code programmatically in iOS?

For example:

number: 900-3440-567
Access C

Answer 1

UIDevice *device = [UIDevice currentDevice];
if ([[device model] isEqualToString:@"iPhone"] ) {
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel:130-032-2837"]]];
} else {
    UIAlertView *notPermitted=[[UIAlertView alloc] initWithTitle:@"Alert" message:@"Your device doesn't support this feature." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
    [notPermitted show];
    [notPermitted release];
}

Answer 2

Using this user can redirect on Call and after the call he/she will automatically redirected to the app. It's working for me and sure about it.

if ([[device model] isEqualToString:@"iPhone"] ) {

    NSString *phoneNumber = [@"telprompt://" stringByAppendingString:cellNameStr];
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];

} else {

    UIAlertView *warning =[[UIAlertView alloc] initWithTitle:@"Alert" message:@"Your device doesn't support this feature." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];

    [warning show];
}

Answer 3

It's not possible to dial programmatically a phone number that includes number and access code.

The Apple Developer Library gives the following info:

"...the Phone application supports most, but not all, of the special characters in the tel scheme. Specifically, if a URL contains the * or # characters, the Phone application does not attempt to dial the corresponding phone number."

See: Apple URL Scheme Reference

Answer 4

Swift 5.0: In case someone needed an updated swift code:

private func callNumber(phoneNumber:String) {
    if let phoneCallURL:NSURL = NSURL(string: "tel://\(phoneNumber)") {
        let application:UIApplication = UIApplication.shared
        if (application.canOpenURL(phoneCallURL as URL)) {
            if #available(iOS 10.0, *) {
                UIApplication.shared.open(phoneCallURL as URL)
            } else {
                UIApplication.shared.openURL(phoneCallURL as URL)
            }
        }
    }
}

Answer 5

You can programmatically dial phone numbers using UIApplication's openURL: method (see example below). I'm unsure if access codes are supported, but this is at least a starting point.

NSURL *URL = [NSURL URLWithString:@"tel://900-3440-567"];
[[UIApplication sharedApplication] openURL:URL];

Edit: See the Apple URL Scheme Reference and the UIApplication Class Reference for more information.

Answer 6

follow the tutorial

http://www.makebetterthings.com/blogs/iphone/open-phone-sms-email-map-and-browser-apps-in-iphone-sdk/

to call a number use -

NSURL *url = [NSURL URLWithString:@"tel://012-4325-234"];
[[UIApplication sharedApplication] openURL:url];

to open your app after call finished use -

(Note: telprompt is undocumented)

NSURL *url = [NSURL URLWithString:@"telprompt://012-4325-234"];
[[UIApplication sharedApplication] openURL:url];