How to implement private method in ES6 class with Traceur [duplicate]

Answer 1

I hope this can be helpful. :)

I. Declaring vars, functions inside IIFE(Immediately-invoked function expression), those can be used only in the anonymous function. (It can be good to use "let, const" keywords without using 'var' when you need to change code for ES6.)

let Name = (function() {
  const _privateHello = function() {
  }
  class Name {
    constructor() {
    }
    publicMethod() {
      _privateHello()
    }
  }
  return Name;
})();

II. WeakMap object can be good for memoryleak trouble.

Stored variables in the WeakMap will be removed when the instance will be removed. Check this article. (Managing the private data of ES6 classes)

let Name = (function() {
  const _privateName = new WeakMap();
})();

III. Let's put all together.

let Name = (function() {
  const _privateName = new WeakMap();
  const _privateHello = function(fullName) {
    console.log("Hello, " + fullName);
  }

  class Name {
    constructor(firstName, lastName) {
      _privateName.set(this, {firstName: firstName, lastName: lastName});
    }
    static printName(name) {
      let privateName = _privateName.get(name);
      let _fullname = privateName.firstName + " " + privateName.lastName;
      _privateHello(_fullname);
    }
    printName() {
      let privateName = _privateName.get(this);
      let _fullname = privateName.firstName + " " + privateName.lastName;
      _privateHello(_fullname);
    }
  }

  return Name;
})();

var aMan = new Name("JH", "Son");
aMan.printName(); // "Hello, JH Son"
Name.printName(aMan); // "Hello, JH Son"

Answer 2

As Marcelo Lazaroni has already said,

Although currently there is no way to declare a method or property as private, ES6 modules are not in the global namespace. Therefore, anything that you declare in your module and do not export will not be available to any other part of your program, but will still be available to your module during run time.

But his example didn't show how the private method could access members of the instance of the class. Max shows us some good examples of how access instance members through binding or the alternative of using a lambda method in the constructor, but I would like to add one more simple way of doing it: passing the instance as a parameter to the private method. Doing it this way would lead Max's MyClass to look like this:

function myPrivateFunction(myClass) {
  console.log("My property: " + myClass.prop);
}

class MyClass() {
  constructor() {
    this.prop = "myProp";
  }
  testMethod() {
    myPrivateFunction(this);
  }
}
module.exports = MyClass;

Which way you do it really comes down to personal preference.

Answer 3

Have you considered using factory functions? They usually are a much better alternative to classes or constructor functions in Javascript. Here is an example of how it works:

function car () {

    var privateVariable = 4

    function privateFunction () {}

    return {

        color: 'red',

        drive: function (miles) {},

        stop: function() {}

        ....

    }

}

Thanks to closures you have access to all private functions and variabels inside the returned object, but you can not access them from outside.

Answer 4

Although currently there is no way to declare a method or property as private, ES6 modules are not in the global namespace. Therefore, anything that you declare in your module and do not export will not be available to any other part of your program, but will still be available to your module during run time. Thus, you have private properties and methods :)

Here is an example (in test.js file)

function tryMe1(a) {
  console.log(a + 2);
}

var tryMe2 = 1234;

class myModule {
  tryMe3(a) {
    console.log(a + 100);
  }

  getTryMe1(a) {
    tryMe1(a);
  }

  getTryMe2() {
    return tryMe2;
  }
}

// Exports just myModule class. Not anything outside of it.
export default myModule; 

In another file

import MyModule from './test';

let bar = new MyModule();

tryMe1(1); // ReferenceError: tryMe1 is not defined
tryMe2; // ReferenceError: tryMe2 is not defined
bar.tryMe1(1); // TypeError: bar.tryMe1 is not a function
bar.tryMe2; // undefined

bar.tryMe3(1); // 101
bar.getTryMe1(1); // 3
bar.getTryMe2(); // 1234

Answer 5

As alexpods says, there is no dedicated way to do this in ES6. However, for those interested, there is also a proposal for the bind operator which enables this sort of syntax:

function privateMethod() {
  return `Hello ${this.name}`;
}

export class Animal {
  constructor(name) {
    this.name = name;
  }
  publicMethod() {
    this::privateMethod();
  }
}

Once again, this is just a proposal. Your mileage may vary.

Answer 6

You can use Symbol

var say = Symbol()

function Cat(){
  this[say]() // call private methos
}

Cat.prototype[say] = function(){ alert('im a private') }

P.S. alexpods is not correct. he get protect rather than private, since inheritance is a name conflict

Actually you can use var say = String(Math.random()) instead Symbol

IN ES6:

var say = Symbol()

class Cat {

  constructor(){
    this[say]() // call private
  }

  [say](){
    alert('im private')
  }

}