Check if a Python list item contains a string inside another string

Question

I have a list:

my_list = [\'abc-123\', \'def-456\', \'ghi-789\', \'abc-456\']

and want to search for items that contain the string \'

Answer 1

I did a search, which requires you to input a certain value, then it will look for a value from the list which contains your input:

my_list = ['abc-123',
        'def-456',
        'ghi-789',
        'abc-456'
        ]

imp = raw_input('Search item: ')

for items in my_list:
    val = items
    if any(imp in val for items in my_list):
        print(items)

Try searching for 'abc'.

Answer 2

def find_dog(new_ls):
    splt = new_ls.split()
    if 'dog' in splt:
        print("True")
    else:
        print('False')


find_dog("Is there a dog here?")

Answer 3

x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]

Answer 4

I am new to Python. I got the code below working and made it easy to understand:

my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for str in my_list:
    if 'abc' in str:
       print(str)

Answer 5

Question : Give the informations of abc

    a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']


    aa = [ string for string in a if  "abc" in string]
    print(aa)

Output =>  ['abc-123', 'abc-456']

Answer 6

I needed the list indices that correspond to a match as follows:

lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']

[n for n, x in enumerate(lst) if 'abc' in x]

output

[0, 3]