How do I use Assert.Throws to assert the type of the exception?

Question

How do I use Assert.Throws to assert the type of the exception and the actual message wording?

Something like this:

Assert.Throws

        

Answer 1

To expand on persistent's answer, and to provide more of the functionality of NUnit, you can do this:

public bool AssertThrows<TException>(
    Action action,
    Func<TException, bool> exceptionCondition = null)
    where TException : Exception
{
    try
    {
        action();
    }
    catch (TException ex)
    {
        if (exceptionCondition != null)
        {
            return exceptionCondition(ex);
        }
        return true;
    }
    catch
    {
        return false;
    }

    return false;
}

Examples:

// No exception thrown - test fails.
Assert.IsTrue(
    AssertThrows<InvalidOperationException>(
        () => {}));

// Wrong exception thrown - test fails.
Assert.IsTrue(
    AssertThrows<InvalidOperationException>(
        () => { throw new ApplicationException(); }));

// Correct exception thrown - test passes.
Assert.IsTrue(
    AssertThrows<InvalidOperationException>(
        () => { throw new InvalidOperationException(); }));

// Correct exception thrown, but wrong message - test fails.
Assert.IsTrue(
    AssertThrows<InvalidOperationException>(
        () => { throw new InvalidOperationException("ABCD"); },
        ex => ex.Message == "1234"));

// Correct exception thrown, with correct message - test passes.
Assert.IsTrue(
    AssertThrows<InvalidOperationException>(
        () => { throw new InvalidOperationException("1234"); },
        ex => ex.Message == "1234"));