List files with certain extensions with ls and grep

Question

I just want to get the files from the current dir and only output .mp4 .mp3 .exe files nothing else. So I thought I could just do this:

ls | grep \\.mp4$ | g         


        

Answer 1

Here is one example that worked for me.

find <mainfolder path> -name '*myfiles.java' | xargs -n 1 basename

Answer 2

Use regular expressions with find:

find . -iregex '.*\.\(mp3\|mp4\|exe\)' -printf '%f\n'

If you're piping the filenames:

find . -iregex '.*\.\(mp3\|mp4\|exe\)' -printf '%f\0' | xargs -0 dosomething

This protects filenames that contain spaces or newlines.

OS X find only supports alternation when the -E (enhanced) option is used.

find -E . -regex '.*\.(mp3|mp4|exe)'

Answer 3

it is easy try to use this command :

ls | grep \.txt$ && ls | grep \.exe

Answer 4

ls | grep "\.mp4$
\.mp3$
\.exe$"

Answer 5

Just in case: why don't you use find?

find -iname '*.mp3' -o -iname '*.exe' -o -iname '*.mp4'

Answer 6

No need for grep. Shell wildcards will do the trick.

ls *.mp4 *.mp3 *.exe

If you have run

shopt -s nullglob

then unmatched globs will be removed altogether and not be left on the command line unexpanded.

If you want case-insensitive globbing (so *.mp3 will match foo.MP3):

shopt -s nocaseglob