Just have a quick question. I\'ve looked around the internet quite a bit and I\'ve found a few solutions but none of them have worked yet. Looking at converting a string to
One line version: long n = strtol(s.c_str(), NULL, base);
.
(s
is the string, and base
is an int
such as 2, 8, 10, 16.)
You can refer to this link for more details of strtol
.
The core idea is to use strtol function, which is included in cstdlib
.
Since strtol
only handles with char
array, we need to convert string
to char
array. You can refer to this link.
An example:
#include <iostream>
#include <string> // string type
#include <bitset> // bitset type used in the output
int main(){
s = "1111000001011010";
long t = strtol(s.c_str(), NULL, 2); // 2 is the base which parse the string
cout << s << endl;
cout << t << endl;
cout << hex << t << endl;
cout << bitset<16> (t) << endl;
return 0;
}
which will output:
1111000001011010
61530
f05a
1111000001011010