Getting Django admin url for an object

Question

Before Django 1.0 there was an easy way to get the admin url of an object, and I had written a small filter that I\'d use like this:

Answer 1

Essentially the same as Mike Ramirez's answer, but simpler and closer in stylistics to django standard get_absolute_url method:

from django.urls import reverse

def get_admin_url(self):
    return reverse('admin:%s_%s_change' % (self._meta.app_label, self._meta.model_name),
                   args=[self.id])

Answer 2

I solved this by changing the expression to:

reverse( 'django-admin', args=["%s/%s/%s/" % (app_label, model_name, object_id)] )

This requires/assumes that the root url conf has a name for the "admin" url handler, mainly that name is "django-admin",

i.e. in the root url conf:

url(r'^admin/(.*)', admin.site.root, name='django-admin'),

It seems to be working, but I'm not sure of its cleanness.

Answer 3

For pre 1.1 django it is simple (for default admin site instance):

reverse('admin_%s_%s_change' % (app_label, model_name), args=(object_id,))

Answer 4

You can use the URL resolver directly in a template, there's no need to write your own filter. E.g.

{% url 'admin:index' %}

{% url 'admin:polls_choice_add' %}

{% url 'admin:polls_choice_change' choice.id %}

{% url 'admin:polls_choice_changelist' %}

Ref: Documentation

Answer 5

Here's another option, using models:

Create a base model (or just add the admin_link method to a particular model)

class CommonModel(models.Model):
    def admin_link(self):
        if self.pk:
            return mark_safe(u'<a target="_blank" href="../../../%s/%s/%s/">%s</a>' % (self._meta.app_label,
                    self._meta.object_name.lower(), self.pk, self))
        else:
            return mark_safe(u'')
    class Meta:
        abstract = True

Inherit from that base model

   class User(CommonModel):
        username = models.CharField(max_length=765)
        password = models.CharField(max_length=192)

Use it in a template

{{ user.admin_link }}

Or view

user.admin_link()

Answer 6

I had a similar issue where I would try to call reverse('admin_index') and was constantly getting django.core.urlresolvers.NoReverseMatch errors.

Turns out I had the old format admin urls in my urls.py file.

I had this in my urlpatterns:

(r'^admin/(.*)', admin.site.root),

which gets the admin screens working but is the deprecated way of doing it. I needed to change it to this:

(r'^admin/', include(admin.site.urls) ),

Once I did that, all the goodness that was promised in the Reversing Admin URLs docs started working.