How can I convert tabs to spaces in every file of a directory (possibly recursively)?
Also, is there a way of setting the number of spaces per tab?
Use backslash-escaped sed
.
On linux:
Replace all tabs with 1 hyphen inplace, in all *.txt files:
sed -i $'s/\t/-/g' *.txt
Replace all tabs with 1 space inplace, in all *.txt files:
sed -i $'s/\t/ /g' *.txt
Replace all tabs with 4 spaces inplace, in all *.txt files:
sed -i $'s/\t/ /g' *.txt
On a mac:
Replace all tabs with 4 spaces inplace, in all *.txt files:
sed -i '' $'s/\t/ /g' *.txt
Simple replacement with sed
is okay but not the best possible solution. If there are "extra" spaces between the tabs they will still be there after substitution, so the margins will be ragged. Tabs expanded in the middle of lines will also not work correctly. In bash
, we can say instead
find . -name '*.java' ! -type d -exec bash -c 'expand -t 4 "$0" > /tmp/e && mv /tmp/e "$0"' {} \;
to apply expand
to every Java file in the current directory tree. Remove / replace the -name
argument if you're targeting some other file types. As one of the comments mentions, be very careful when removing -name
or using a weak, wildcard. You can easily clobber repository and other hidden files without intent. This is why the original answer included this:
You should always make a backup copy of the tree before trying something like this in case something goes wrong.
I like the "find" example above for the recursive application. To adapt it to be non-recursive, only changing files in the current directory that match a wildcard, the shell glob expansion can be sufficient for small amounts of files:
ls *.java | awk '{print "expand -t 4 ", $0, " > /tmp/e; mv /tmp/e ", $0}' | sh -v
If you want it silent after you trust that it works, just drop the -v
on the sh
command at the end.
Of course you can pick any set of files in the first command. For example, list only a particular subdirectory (or directories) in a controlled manner like this:
ls mod/*/*.php | awk '{print "expand -t 4 ", $0, " > /tmp/e; mv /tmp/e ", $0}' | sh
Or in turn run find(1) with some combination of depth parameters etc:
find mod/ -name '*.php' -mindepth 1 -maxdepth 2 | awk '{print "expand -t 4 ", $0, " > /tmp/e; mv /tmp/e ", $0}' | sh
One can use vim
for that:
find -type f \( -name '*.css' -o -name '*.html' -o -name '*.js' -o -name '*.php' \) -execdir vim -c retab -c wq {} \;
As Carpetsmoker stated, it will retab according to your vim
settings. And modelines in the files, if any. Also, it will replace tabs not only at the beginning of the lines. Which is not what you generally want. E.g., you might have literals, containing tabs.
Use the vim-way:
$ ex +'bufdo retab' -cxa **/*.*
globstar
(**
) for recursion, activate by shopt -s globstar
.**/*.c
.To modify tabstop, add +'set ts=2'
.
However the down-side is that it can replace tabs inside the strings.
So for slightly better solution (by using substitution), try:
$ ex -s +'bufdo %s/^\t\+/ /ge' -cxa **/*.*
Or by using ex
editor + expand
utility:
$ ex -s +'bufdo!%!expand -t2' -cxa **/*.*
For trailing spaces, see: How to remove trailing whitespaces for multiple files?
You may add the following function into your .bash_profile
:
# Convert tabs to spaces.
# Usage: retab *.*
# See: https://stackoverflow.com/q/11094383/55075
retab() {
ex +'set ts=2' +'bufdo retab' -cxa $*
}
To convert all Java files recursively in a directory to use 4 spaces instead of a tab:
find . -type f -name *.java -exec bash -c 'expand -t 4 {} > /tmp/stuff;mv /tmp/stuff {}' \;