Is there a nice easy way to drop all tables from a MySQL database, ignoring any foreign key constraints that may be in there?
Here is SurlyDre's stored procedure modified so that foreign keys are ignored:
DROP PROCEDURE IF EXISTS `drop_all_tables`;
DELIMITER $$
CREATE PROCEDURE `drop_all_tables`()
BEGIN
DECLARE _done INT DEFAULT FALSE;
DECLARE _tableName VARCHAR(255);
DECLARE _cursor CURSOR FOR
SELECT table_name
FROM information_schema.TABLES
WHERE table_schema = SCHEMA();
DECLARE CONTINUE HANDLER FOR NOT FOUND SET _done = TRUE;
SET FOREIGN_KEY_CHECKS = 0;
OPEN _cursor;
REPEAT FETCH _cursor INTO _tableName;
IF NOT _done THEN
SET @stmt_sql = CONCAT('DROP TABLE ', _tableName);
PREPARE stmt1 FROM @stmt_sql;
EXECUTE stmt1;
DEALLOCATE PREPARE stmt1;
END IF;
UNTIL _done END REPEAT;
CLOSE _cursor;
SET FOREIGN_KEY_CHECKS = 1;
END$$
DELIMITER ;
call drop_all_tables();
DROP PROCEDURE IF EXISTS `drop_all_tables`;
Building on the answer by @Dion Truter and @Wade Williams, the following shell script will drop all tables, after first showing what it is about to run, and giving you a chance to abort using Ctrl-C.
#!/bin/bash
DB_HOST=xxx
DB_USERNAME=xxx
DB_PASSWORD=xxx
DB_NAME=xxx
CMD="mysql -sN -h ${DB_HOST} -u ${DB_USERNAME} -p${DB_PASSWORD} ${DB_NAME}"
# Generate the drop statements
TMPFILE=/tmp/drop-${RANDOM}.sql
echo 'SET FOREIGN_KEY_CHECKS = 0;' > ${TMPFILE}
${CMD} $@ >> ${TMPFILE} << ENDD
SELECT concat('DROP TABLE IF EXISTS \`', table_name, '\`;')
FROM information_schema.tables
WHERE table_schema = '${DB_NAME}';
ENDD
echo 'SET FOREIGN_KEY_CHECKS = 1;' >> ${TMPFILE}
# Warn what we are about to do
echo
cat ${TMPFILE}
echo
echo "Press ENTER to proceed (or Ctrl-C to abort)."
read
# Run the SQL
echo "Dropping tables..."
${CMD} $@ < ${TMPFILE}
echo "Exit status is ${?}."
rm ${TMPFILE}
I use the following with a MSSQL server:
if (DB_NAME() = 'YOUR_DATABASE')
begin
while(exists(select 1 from INFORMATION_SCHEMA.TABLE_CONSTRAINTS where CONSTRAINT_TYPE='FOREIGN KEY'))
begin
declare @sql nvarchar(2000)
SELECT TOP 1 @sql=('ALTER TABLE ' + TABLE_SCHEMA + '.[' + TABLE_NAME + '] DROP CONSTRAINT [' + CONSTRAINT_NAME + ']')
FROM information_schema.table_constraints
WHERE CONSTRAINT_TYPE = 'FOREIGN KEY'
exec (@sql)
PRINT @sql
end
while(exists(select 1 from INFORMATION_SCHEMA.TABLES))
begin
declare @sql2 nvarchar(2000)
SELECT TOP 1 @sql2=('DROP TABLE ' + TABLE_SCHEMA + '.[' + TABLE_NAME + ']')
FROM INFORMATION_SCHEMA.TABLES
exec (@sql2)
PRINT @sql2
end
end
else
print('Only run this script on the development server!!!!')
Replace YOUR_DATABASE with the name of your database or remove the entire IF statement (I like the added safety).
I came up with this modification on Dion Truter's answer to make it easier with many tables:
SET GROUP_CONCAT_MAX_LEN = 10000000;
SELECT CONCAT('SET FOREIGN_KEY_CHECKS=0;\n',
GROUP_CONCAT(CONCAT('DROP TABLE IF EXISTS `', table_name, '`')
SEPARATOR ';\n'),
';\nSET FOREIGN_KEY_CHECKS=1;')
FROM information_schema.tables
WHERE table_schema = 'SchemaName';
This returns the entire thing in one field, so you can copy once and delete all the tables (use Copy Field Content (unquoted)
in Workbench). If you have a LOT of tables, you may hit some limits on GROUP_CONCAT()
. If so, increase the max len variable (and max_allowed_packet
, if necessary).
Just put here some useful comment made by Jonathan Watt to drop all tables
MYSQL="mysql -h HOST -u USERNAME -pPASSWORD DB_NAME"
$MYSQL -BNe "show tables" | awk '{print "set foreign_key_checks=0; drop table `" $1 "`;"}' | $MYSQL
unset MYSQL
It helps me and I hope it could be useful
From http://www.devdaily.com/blog/post/mysql/drop-mysql-tables-in-any-order-foreign-keys:
SET FOREIGN_KEY_CHECKS = 0;
drop table if exists customers;
drop table if exists orders;
drop table if exists order_details;
SET FOREIGN_KEY_CHECKS = 1;
(Note that this answers how to disable foreign key checks in order to be able to drop the tables in arbitrary order. It does not answer how to automatically generate drop-table statements for all existing tables and execute them in a single script. Jean's answer does.)