How to get full path of a file?

Question

Is there an easy way I can print the full path of file.txt ?

file.txt = /nfs/an/disks/jj/home/dir/file.txt

The

Answer 1

This will work for both file and folder:

getAbsolutePath(){
    [[ -d $1 ]] && { cd "$1"; echo "$(pwd -P)"; } || 
    { cd "$(dirname "$1")" || exit 1; echo "$(pwd -P)/$(basename "$1")"; }
}

Answer 2

You can save this in your shell.rc or just put in console

function absolute_path { echo "$PWD/$1"; }
alias ap="absolute_path"

example:

ap somefile.txt

will output

/home/user/somefile.txt

Answer 3

You could use the fpn (full path name) script:

% pwd
/Users/adamatan/bins/scripts/fpn

% ls
LICENSE   README.md fpn.py

% fpn *
/Users/adamatan/bins/scripts/fpn/LICENSE
/Users/adamatan/bins/scripts/fpn/README.md
/Users/adamatan/bins/scripts/fpn/fpn.py

fpn is not a standard Linux package, but it's a free and open github project and you could set it up in a minute.

Answer 4

find $PWD -type f | grep "filename"

or

find $PWD -type f -name "*filename*"

Answer 5

In a similar scenario, I'm launching a cshell script from some other location. For setting the correct absolute path of the script so that it runs in the designated directory only, I'm using the following code:

set script_dir = `pwd`/`dirname $0`

$0 stores the exact string how the script was executed.

For e.g. if the script was launched like this: $> ../../test/test.csh, $script_dir will contain /home/abc/sandbox/v1/../../test

Answer 6

Create a function like the below (echoes the absolute path of a file with pwd and adds the file at the end of the path:

abspath() { echo $(pwd "$1")/"$1"; }

Now you can just find any file path:

abspath myfile.ext