I am trying hard to compare two floating point numbers within a bash script. I have to variables, e.g.
let num1=3.17648e-22
let num2=1.5
No
I used the answers from here and put them in a function, you can use it like this:
is_first_floating_number_bigger 1.5 1.2
result="${__FUNCTION_RETURN}"
Once called, echo $result
will be 1
in this case, otherwise 0
.
The function:
is_first_floating_number_bigger () {
number1="$1"
number2="$2"
[ ${number1%.*} -eq ${number2%.*} ] && [ ${number1#*.} \> ${number2#*.} ] || [ ${number1%.*} -gt ${number2%.*} ];
result=$?
if [ "$result" -eq 0 ]; then result=1; else result=0; fi
__FUNCTION_RETURN="${result}"
}
Or a version with debug output:
is_first_floating_number_bigger () {
number1="$1"
number2="$2"
echo "... is_first_floating_number_bigger: comparing ${number1} with ${number2} (to check if the first one is bigger)"
[ ${number1%.*} -eq ${number2%.*} ] && [ ${number1#*.} \> ${number2#*.} ] || [ ${number1%.*} -gt ${number2%.*} ];
result=$?
if [ "$result" -eq 0 ]; then result=1; else result=0; fi
echo "... is_first_floating_number_bigger: result is: ${result}"
if [ "$result" -eq 0 ]; then
echo "... is_first_floating_number_bigger: ${number1} is not bigger than ${number2}"
else
echo "... is_first_floating_number_bigger: ${number1} is bigger than ${number2}"
fi
__FUNCTION_RETURN="${result}"
}
Just save the function in a separated .sh
file and include it like this:
. /path/to/the/new-file.sh
Of course, if you don't need really floating-point arithmetic, just arithmetic on e.g. dollar values where there are always exactly two decimal digits, you might just drop the dot (effectively multiplying by 100) and compare the resulting integers.
if [[ $((10#${num1/.})) < $((10#${num2/.})) ]]; then
...
This obviously requires you to be sure that both values have the same number of decimal places.
Use korn shell, in bash you may have to compare the decimal part separately
#!/bin/ksh
X=0.2
Y=0.2
echo $X
echo $Y
if [[ $X -lt $Y ]]
then
echo "X is less than Y"
elif [[ $X -gt $Y ]]
then
echo "X is greater than Y"
elif [[ $X -eq $Y ]]
then
echo "X is equal to Y"
fi
It's better to use awk
for non integer mathematics. You can use this bash utility function:
numCompare() {
awk -v n1="$1" -v n2="$2" 'BEGIN {printf "%s " (n1<n2?"<":">=") " %s\n", n1, n2}'
}
And call it as:
numCompare 5.65 3.14e-22
5.65 >= 3.14e-22
numCompare 5.65e-23 3.14e-22
5.65e-23 < 3.14e-22
numCompare 3.145678 3.145679
3.145678 < 3.145679
beware when comparing numbers that are package versions, like checking if grep 2.20 is greater than version 2.6:
$ awk 'BEGIN { print (2.20 >= 2.6) ? "YES" : "NO" }'
NO
$ awk 'BEGIN { print (2.2 >= 2.6) ? "YES" : "NO" }'
NO
$ awk 'BEGIN { print (2.60 == 2.6) ? "YES" : "NO" }'
YES
I solved such problem with such shell/awk function:
# get version of GNU tool
toolversion() {
local prog="$1" operator="$2" value="$3" version
version=$($prog --version | awk '{print $NF; exit}')
awk -vv1="$version" -vv2="$value" 'BEGIN {
split(v1, a, /\./); split(v2, b, /\./);
if (a[1] == b[1]) {
exit (a[2] '$operator' b[2]) ? 0 : 1
}
else {
exit (a[1] '$operator' b[1]) ? 0 : 1
}
}'
}
if toolversion grep '>=' 2.6; then
# do something awesome
fi
This can be done more conveniently using Bash's numeric context:
if (( $(echo "$num1 > $num2" |bc -l) )); then
…
fi
Piping through the basic calculator command bc
returns either 1 or 0.
The option -l
is equivalent to --mathlib
; it loads the standard math library.
Enclosing the whole expression between double parenthesis (( ))
will translate these values to respectively true or false.
Please, ensure that the bc
basic calculator package is installed.
This equally works for floats in scientific format, provided a capital letter E
is employed, e.g. num1=3.44E6