Getting StaleElementReferenceException while trying print the link names

Question

I\'m trying to print first 5 pages links displayed in google search.. But getting StateElementReferenceException Not sure which one went wrong..

    public          


        

Answer 1

This is due to referencing object after moving to another page. please try to add the following lines inside the for loops at the end. It may resolve stale reference issue.

    driver.navigate().back();
    fiveLinks=driver.findElements(By.xpath(".//*[@id='nav']/tbody/tr/td/a"));

Answer 2

A couple of things:

1. Your script prints the result from the first 2 pages as expected.
2. When you call printLinksName() for the first time it works.
3. Next, you are storing the 10 PageNumbers in a Generic List of type WebElement.
4. First time within the for() loop you are clicking on the WebElement of Page 2 and then printing all the links by calling printLinksName().
5. While you are in the second iteration within for() loop, the reference of List<WebElement> fiveLinks is lost as the DOM have changed. Hence, you see StaleElementReferenceException.

Solution

A simple solution to avoid StaleElementReferenceException would be to move the line of code List<WebElement> fiveLinks=driver.findElements(By.xpath(".//*[@id='nav']/tbody/tr/td/a")); with in the for() loop. So your code block will look like:

    import java.util.List;
    import java.util.concurrent.TimeUnit;

    import org.openqa.selenium.By;
    import org.openqa.selenium.Keys;
    import org.openqa.selenium.WebDriver;
    import org.openqa.selenium.WebElement;
    import org.openqa.selenium.firefox.FirefoxDriver;

    public class Q44970712_stale 
    {

        static WebDriver driver = null;

        public static void main(String[] args)  throws InterruptedException
        {
        System.setProperty("webdriver.gecko.driver", "C:\\Utility\\BrowserDrivers\\geckodriver.exe");
        driver=new FirefoxDriver();
        driver.manage().window().maximize();
        driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
        driver.get("https://www.google.co.in/");
        //driver.findElement(By.xpath("//input[class='gsfi']")).sendKeys("Banduchode");;
        WebElement search=driver.findElement(By.cssSelector("input#lst-ib"));
        search.sendKeys("Banduchode");
        search.sendKeys(Keys.ENTER);
        printLinksName();



        for(int i=0;i<5;i++)
        {
            List<WebElement> fiveLinks=driver.findElements(By.xpath(".//*[@id='nav']/tbody/tr/td/a"));
            System.out.println(fiveLinks.get(i).getText());
            fiveLinks.get(i).click();
            Thread.sleep(5000);
            printLinksName();
        }
        }

        public static void printLinksName() throws InterruptedException
        {
            List<WebElement> allLinks=driver.findElements(By.xpath("//*[@id='rso']/div/div/div/div/div/h3/a"));
            System.out.println(allLinks.size()); 

            //print all list        
            for(int i=0;i<allLinks.size();i++)
            {
            System.out.println("Sno"+(i+1)+":"+allLinks.get(i).getText());

            }   
        }

    }

Note: In this simple solution when you finish printing the second page, next when you will create List<WebElement> fiveLinks through xpath with .//*[@id='nav']/tbody/tr/td/a for second time, Page 1 is the first element which gets stored in the fiveLinks List. Hence you may be again redirected to Page 1. To avoid that you may consider to take help of xpath with proper indexing.

Answer 3

your script is trying to click on each link from the first page, which brings you to a new page. once it completes work on that page, it doesn't seem to return to the first page, so the script can't find the next link in your list.

even if it did return to the first page, you would still have a stale element because the page has been reloaded. You'll need to keep track of the links in the first page by something else (like the href maybe?), and find the link again by that identifier before you click on it.