Modifying a list while iterating when programming with python [duplicate]

Answer 1

def formatter(vals):
    def clamp(x):
        '''Fixes the values between 0 and 100'''
        return max(0, min(100, x))

    def string_formatter(x):
        '''Formats the values into a string with width 4'''
        if x == 100:
            return "{:<4g}".format(x)
        elif x == 0:
            return ' '*4
        else: 
            return "{:>4.1f}".format(x)

    return [string_formatter(clamp(i)) for i in vals]

Answer 2

Check out the use of the format command used for string formatting before continuing. This shoud allow you to safely convert any input to the format you need. The only thing here is that you need conditional formatting. Which means that the format string should be dependent upon the number that is formatting. This can easily be done like so:

fmtStr = lambda x: ' 100' if x >= 100 else ('    ' if x < 0 else '{:4.1f}')

This is a function that takes a number and returns a different format string depending upon the value it is given. Now given this value, all you need to do is to format every element in the list that you have. Easiest and the most Pythonic way is to do a list comprehension. So let us generate a list, and format it ...

vals    = random.random(103)*300 - 150
strVals = [fmtStr(i).format(i) for i in val]

Hope this helps.

Answer 3

This should work

AvailibilityLine1 = 1.9
AvailibilityLine2 = 45.9
PerformanceLine1 = 76.5
PerformanceLine2 = 99.9
QualityLine1 = 100.0
QualityLine2 = 0.0

#these come in as floats with a single decimal space, ex:99.9
val = [AvailibilityLine1, AvailibilityLine2, PerformanceLine1, 
       PerformanceLine2, QualityLine1, QualityLine2] 

j = 0
for i in val:
    if i >= float(100):
        val[j] = "100 "
    elif i >= 10 and i < 100:
        val[j] = str(val[j])
    elif i > 0 and  i < 10:
        val[j] = " " + str(val[j])
    elif i <= 0:
        val[j] = "    "    #insert 4 spaces
    else:
        val[j] = "    "    #insert 4 spaces if all else fails
    j = j + 1

print val

Output

>>> [' 1.9', '45.9', '76.5', '99.9', '100 ', '    ']

problems in your code:

1. Initialization of counter J should be outside the for loop
2. You are assigning whole list (val) to list index in 2nd and 3rd condition of if-else

Answer 4

You can use enumerate and string formatting to achieve this:

num_list = [1.0, 2.0, 3.0, 4.0, 5.0, 6.0]
for _index, _value in enumerate(num_list):
    if val <= 0:
        _value = ""  # If value is 0 or lower, just change it to empty string
    elif val >= 100
        _value = 100  # If value is greater than or equal to 100.0, make it 100
    num_list[_index] = "{:>4}".format(_value)

>> num_list
>> [' 1.0', ' 2.0', ' 3.0', ' 4.0', ' 5.0', ' 6.0']

In format, "{:<4}" defines the text formatting, < means align text to left while, > means align it right and ^ means center it. 4 defines the final length. It apply the preferred alignment and fill the rest with spaces. If you want to use a filling character instead of spaces, you can use it like

num_list[_index] = "{:*<4}".format(_value)

>> num_list
>> ['1.0*', '2.0*', '3.0*', '4.0*', '5.0*', '6.0*']

Where * is your fill character

Answer 5

you can access and change the list value using index following way:

val= [1,2,3,4,5,6,50,110]
for i in xrange(len(val)):
    if val[i] >= 100:
       val[i] = "100 "                                                           
    elif val[i] >= 10 and val[i] < 100:
       val[i] = str(val[i])
    elif val[i] > 0 and  val[i] < 10:
       val[i] = " " + str(val[i])
    elif val[i] <= 0:
       val[i] = "    "    #insert 4 spaces
    else:
       val[i] = "    "    #insert 4 spaces if all else fails

print val