Simple regular expression for a decimal with a precision of 2

Question

What is the regular expression for a decimal with a precision of 2?

Valid examples:

123.12
2
56754
92929292929292.12
0.21
3.1

Answer 1

adding my answer too, someone might find it useful or may be correct mine too.

function getInteger(int){
  var regx = /^[-+]?[\d.]+$/g;
  return regx.test(int);
}


alert(getInteger('-11.11'));

Answer 2

This worked with me:

(-?[0-9]+(\.[0-9]+)?)

Group 1 is the your float number and group 2 is the fraction only.

Answer 3

^[0-9]+(\.[0-9]{1,2})?$

And since regular expressions are horrible to read, much less understand, here is the verbose equivalent:

^                         # Start of string
 [0-9]+                   # Require one or more numbers
       (                  # Begin optional group
        \.                # Point must be escaped or it is treated as "any character"
          [0-9]{1,2}      # One or two numbers
                    )?    # End group--signify that it's optional with "?"
                      $   # End of string

You can replace [0-9] with \d in most regular expression implementations (including PCRE, the most common). I've left it as [0-9] as I think it's easier to read.

Also, here is the simple Python script I used to check it:

import re
deci_num_checker = re.compile(r"""^[0-9]+(\.[0-9]{1,2})?$""")

valid = ["123.12", "2", "56754", "92929292929292.12", "0.21", "3.1"]
invalid = ["12.1232", "2.23332", "e666.76"]

assert len([deci_num_checker.match(x) != None for x in valid]) == len(valid)
assert [deci_num_checker.match(x) == None for x in invalid].count(False) == 0

Answer 4

Try this

 (\\+|-)?([0-9]+(\\.[0-9]+))

It will allow positive and negative signs also.

Answer 5

Chrome 56 is not accepting this kind of patterns (Chrome 56 is accpeting 11.11. an additional .) with type number, use type as text as progress.

Answer 6

I tried one with my project. This allows numbers with + | - signs as well.

/^(\+|-)?[0-9]{0,}((\.){1}[0-9]{1,}){0,1}$/