RegEx: Grabbing values between quotation marks

Question

I have a value like this:

\"Foo Bar\" \"Another Value\" something else

What regex will return the

Answer 1

In general, the following regular expression fragment is what you are looking for:

"(.*?)"

This uses the non-greedy *? operator to capture everything up to but not including the next double quote. Then, you use a language-specific mechanism to extract the matched text.

In Python, you could do:

>>> import re
>>> string = '"Foo Bar" "Another Value"'
>>> print re.findall(r'"(.*?)"', string)
['Foo Bar', 'Another Value']

Answer 2

A supplementary answer for the subset of Microsoft VBA coders only one uses the library Microsoft VBScript Regular Expressions 5.5 and this gives the following code

Sub TestRegularExpression()

    Dim oRE As VBScript_RegExp_55.RegExp    '* Tools->References: Microsoft VBScript Regular Expressions 5.5
    Set oRE = New VBScript_RegExp_55.RegExp

    oRE.Pattern = """([^""]*)"""


    oRE.Global = True

    Dim sTest As String
    sTest = """Foo Bar"" ""Another Value"" something else"

    Debug.Assert oRE.test(sTest)

    Dim oMatchCol As VBScript_RegExp_55.MatchCollection
    Set oMatchCol = oRE.Execute(sTest)
    Debug.Assert oMatchCol.Count = 2

    Dim oMatch As Match
    For Each oMatch In oMatchCol
        Debug.Print oMatch.SubMatches(0)

    Next oMatch

End Sub