Can I create a Controller that simply returns an image asset?
I would like to route this logic through a controller, whenever a URL such as the following is requeste
UPDATE: There are better options than my original answer. This works outside of MVC quite well but it's better to stick with the built-in methods of returning image content. See up-voted answers.
You certainly can. Try out these steps:
Here's some sample code:
string pathToFile = @"C:\Documents and Settings\some_path.jpg";
byte[] imageData = File.ReadAllBytes(pathToFile);
Response.ContentType = "image/jpg";
Response.BinaryWrite(imageData);
Hope that helps!
Why not go simple and use the tilde ~
operator?
public FileResult TopBanner() {
return File("~/Content/images/topbanner.png", "image/png");
}
if (!System.IO.File.Exists(filePath))
return SomeHelper.EmptyImageResult(); // preventing JSON GET/POST exception
else
return new FilePathResult(filePath, contentType);
SomeHelper.EmptyImageResult()
should return FileResult
with existing image (1x1 transparent, for example).
This is easiest way if you have files stored on local drive.
If files are byte[]
or stream
- then use FileContentResult
or FileStreamResult
as Dylan suggested.
I also encountered similar requirement,
So in my case I make a request to Controller with the image folder path, which in return sends back a ImageResult object.
Following code snippet illustrate the work:
var src = string.Format("/GenericGrid.mvc/DocumentPreviewImageLink?fullpath={0}&routingId={1}&siteCode={2}", fullFilePath, metaInfo.RoutingId, da.SiteCode);
if (enlarged)
result = "<a class='thumbnail' href='#thumb'>" +
"<img src='" + src + "' height='66px' border='0' />" +
"<span><img src='" + src + "' /></span>" +
"</a>";
else
result = "<span><img src='" + src + "' height='150px' border='0' /></span>";
And in the Controller from the the image path I produce the image and return it back to the caller
try
{
var file = new FileInfo(fullpath);
if (!file.Exists)
return string.Empty;
var image = new WebImage(fullpath);
return new ImageResult(new MemoryStream(image.GetBytes()), "image/jpg");
}
catch(Exception ex)
{
return "File Error : "+ex.ToString();
}
you can use File to return a file like View, Content etc
public ActionResult PrintDocInfo(string Attachment)
{
string test = Attachment;
if (test != string.Empty || test != "" || test != null)
{
string filename = Attachment.Split('\\').Last();
string filepath = Attachment;
byte[] filedata = System.IO.File.ReadAllBytes(Attachment);
string contentType = MimeMapping.GetMimeMapping(Attachment);
System.Net.Mime.ContentDisposition cd = new System.Net.Mime.ContentDisposition
{
FileName = filename,
Inline = true,
};
Response.AppendHeader("Content-Disposition", cd.ToString());
return File(filedata, contentType);
}
else { return Content("<h3> Patient Clinical Document Not Uploaded</h3>"); }
}
To expland on Dyland's response slightly:
Three classes implement the FileResult class:
System.Web.Mvc.FileResult
System.Web.Mvc.FileContentResult
System.Web.Mvc.FilePathResult
System.Web.Mvc.FileStreamResult
They're all fairly self explanatory:
FilePathResult
- this is the easiest way and avoids you having to use Streams.FileContentResult
.FileStreamResult
in a similar way to below, but with a MemoryStream
and using GetBuffer()
.Streams
use FileStreamResult
. It's called a FileStreamResult but it takes a Stream
so I'd guess it works with a MemoryStream
.Below is an example of using the content-disposition technique (not tested):
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult GetFile()
{
// No need to dispose the stream, MVC does it for you
string path = Path.Combine(AppDomain.CurrentDomain.BaseDirectory, "App_Data", "myimage.png");
FileStream stream = new FileStream(path, FileMode.Open);
FileStreamResult result = new FileStreamResult(stream, "image/png");
result.FileDownloadName = "image.png";
return result;
}