C# decimal take ceiling 2

Question

I want to round my decimal value like 2.2222 to 2.23. When I use round,

decimal a = Math.Round((decimal)2.222, 2);

When I use ceiling, it c

Answer 1

decimal c = Math.Ceiling((decimal)2.2222*100)/100;

but it's stupid.

Answer 2

public static decimal CeilingAfterPoint(this decimal number, int digitsAfterPoint) {
    return Math.Ceiling(number * (decimal)Math.Pow(10, digitsAfterPoint))
           / (decimal)Math.Pow(10, digitsAfterPoint);
}

Answer 3

try something like

decimal c = Math.Ceiling((decimal)2.222*100)/100;

but it fails if your value is 2.22

Answer 4

I solved my problem..

 string n = "2.2222";
        string[] s = n.Split('.');

        if (s[1].Count() >= 3)
        {
            List<char> z = s[1].ToString().Take(2).ToList();
            int c=Convert.ToInt32(z[0].ToString() + z[1].ToString()) + 1;
          //  int b = Convert.ToInt32(s[1].ElementAt(0).ToString() + s[1].ElementAt(1).ToString()) + 1;
            string output= s[0] + "." + c.ToString();            
        }

now any number can put ,it will take 2 decimal value and add 1.Thanks.