How to calculate age (in years) based on Date of Birth and getDate()

Question

I have a table listing people along with their date of birth (currently a nvarchar(25))

How can I convert that to a date, and then calculate their age in years?

Answer 1

What about:

DECLARE @DOB datetime
SET @DOB='19851125'   
SELECT Datepart(yy,convert(date,GETDATE())-@DOB)-1900

Wouldn't that avoid all those rounding, truncating and ofsetting issues?

Answer 2

select DATEDIFF(yy,@DATE,GETDATE()) -
case when DATEPART(mm,GETDATE())*100+DATEPART(dd,GETDATE())>=
DATEPART(mm,@DATE)*100+DATEPART(dd,@DATE) THEN 0
ELSE 1 END 

Answer 3

I believe this is similar to other ones posted here.... but this solution worked for the leap year examples 02/29/1976 to 03/01/2011 and also worked for the case for the first year.. like 07/04/2011 to 07/03/2012 which the last one posted about leap year solution did not work for that first year use case.

SELECT FLOOR(DATEDIFF(DAY, @date1 , @date2) / 365.25)

Found here.

Answer 4

This will correctly handle the issues with the birthday and rounding:

DECLARE @dob  datetime
SET @dob='1992-01-09 00:00:00'

SELECT DATEDIFF(YEAR, '0:0', getdate()-@dob)

Answer 5

Here is how i calculate age given a birth date and current date.

select case 
            when cast(getdate() as date) = cast(dateadd(year, (datediff(year, '1996-09-09', getdate())), '1996-09-09') as date)
                then dateDiff(yyyy,'1996-09-09',dateadd(year, 0, getdate()))
            else dateDiff(yyyy,'1996-09-09',dateadd(year, -1, getdate()))
        end as MemberAge
go

Answer 6

I have used this query in our production code for nearly 10 years:

SELECT FLOOR((CAST (GetDate() AS INTEGER) - CAST(Date_of_birth AS INTEGER)) / 365.25) AS Age