Is there possibility to use indexing directly on a function\'s return value? Something like this:
readStr()(2:5)
where readStr()
No, that is not possible in Fortran. You could, however, alter your function to take an additional index array that determines which elements are returned. This example illustrates this possibility using an interface to allow for an optional specification of the indices (simplified greatly thanks to the comment by IanH):
module test_mod
implicit none
contains
function squareOpt( arr, idx ) result(res)
real, intent(in) :: arr(:)
integer, intent(in), optional :: idx(:)
real,allocatable :: res( : )
real :: res_( size(arr) )
integer :: stat
! Calculate as before
res_ = arr*arr
if ( present(idx) ) then
! Take the sub-set
allocate( res(size(idx)), stat=stat )
if ( stat /= 0 ) stop 'Cannot allocate memory!'
res = res_(idx)
else
! Take the the whole array
allocate( res(size(arr)), stat=stat )
if ( stat /= 0 ) stop 'Cannot allocate memory!'
res = res_
endif
end function
end module
program test
use test_mod
implicit none
real :: arr(4)
integer :: idx(2)
arr = [ 1., 2., 3., 4. ]
idx = [ 2, 3]
print *, 'w/o indices',squareOpt(arr)
print *, 'w/ indices',squareOpt(arr, idx)
end program
You can avoid declaring another variable if you use associate
. Whether it is any better or clearer than a temporary variable must be decided by the user. The result has to be stored somewhere anyway.
associate(str=>readStr())
print *, str(2:5)
end associate
It will not be very useful for this specific case with a potentially long string but might be more useful for other similar cases that get linked here as duplicates.
No.
But if it bothers you, you can write your own user defined functions and operators to achieve a similar outcome without having to store the result of the function reference in a separate variable.