Update multiple elements in an array in mongodb [duplicate]

Answer 1

You can achieve it using script.

db.stocks.find().forEach(function (e) {
  var modified = false;
  e.History.forEach(function (o) {
    if (o.status != "PROCESSED") {
      o.flag = true;
      modified = true;
    }
  });
  if (modified) {
    db.stocks.save(e);
  }
});

Answer 2

You need to use the all $[] positional operator to update each element in the array

db.collection.update(
   { "History": { "$elemMatch": { "status": { "$ne": "PROCESSED" } } } }, 
   { "$set": { "History.$[].flag": false } },
   { "multi": true }
)

Answer 3

You can simply do it by using '$' operator. Something like:

 db.stocks.update( {"history.status" : { $not: "PROCESSED" } , 
                { $set: {"history.$.flag": true }} , 
                false , 
                true);

Answer 4

My answer is very similar @Anthony but a two extra parameter( for upsert and multi) are added. For reference You can check official document.

db.stocks.update(
    { "History": { "$elemMatch": { "status": { "$ne": "PROCESSED" } } } }, 
    { "$set": { "History.$[].flag": false }},
     false,              // show that if there is not any document with specified criteria , it will not create a new document.
     ture              // according to document of mongodb if multi is true then more than one document will be updated, other wise only one document will be updated.
)