Undefined index: file

Question

I am getting the undefined index error as I come for the first time in my upload form page or if I move to next page and click on back button then I have the same error mess

Answer 1

"Undefined index" means you're trying to read an array element that doesn't exist.

Your specific problem seems to be that you're trying to read upload data that doesn't exist yet: When you first visit your upload form, there is no $_FILES array (or rather, there's nothing in it), because the form hasn't been submitted. But since you don't check if the form was submitted, these lines net you an error:

//Set Temp Name for upload.
$uploaded->set_tmp_name($_FILES['file']['tmp_name']);
//Set file size
$uploaded->set_file_size($_FILES['file']['size']);
//set file type
$uploaded->set_file_type($_FILES['file']['type']);
//set file name
$uploaded->set_file_name($_FILES['file']['name']);

They're all trying to read the value of $_FILES['file'] to pass them to the methods of $uploaded.

What you need is a check beforehand:

if (isset($_FILES['file'])) {
    $uploaded = new upload;
    //set Max Size
    $uploaded->set_max_size(350000);
    //Set Directory
    $uploaded->set_directory("data");
    //Set Temp Name for upload.
    $uploaded->set_tmp_name($_FILES['file']['tmp_name']);
    //Set file size
    $uploaded->set_file_size($_FILES['file']['size']);
    //set file type
    $uploaded->set_file_type($_FILES['file']['type']);
    //set file name
    $uploaded->set_file_name($_FILES['file']['name']);
    //start copy process
    $uploaded->start_copy();
    if($uploaded->is_ok()) 
        echo " upload is doen.";
    else
        $uploaded->error()."<br>";
}

Answer 2

The error is probably in your upload class. The error message is pretty clear, if that is the actual message you get there is probably a line somewhere in that class that looks for an array key I that is named 'fileUpload'.

Just do a search in your code for 'fileUpload', and add something to check if the key is set, ie

 if(isset($arraywhatever['fileUpload'])) condition to your code.