javascript ajax request without framework

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一向
一向 2020-12-01 22:36

Does anyone know how to make ajax request function that works cross-browser WITHOUT using a javascript framework like jQuery, etc.?

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  • 2020-12-01 22:53

    The XMLHttpRequest object isn't actually all that complicated to use. To be broadly compatible, you have to play a bit of a game to create the object, but after that it's fairly straightforward for simple operations.

    Microsoft has examples on the MSDN page for XMLHttpRequest, including a function for creating the object in a cross-browser way that supports early versions of IE. Here's their example:

    function getXMLHttpRequest() 
    {
        if (window.XMLHttpRequest) {
            return new window.XMLHttpRequest;
        }
        else {
            try {
                return new ActiveXObject("MSXML2.XMLHTTP.3.0");
            }
            catch(ex) {
                return null;
            }
        }
    }
    
    function handler()
    {
        if (oReq.readyState == 4 /* complete */) {
            if (oReq.status == 200) {
                alert(oReq.responseText);
            }
        }
    }
    
    var oReq = getXMLHttpRequest();
    
    if (oReq != null) {
        oReq.open("GET", "http://localhost/test.xml", true);
        oReq.onreadystatechange = handler;
        oReq.send();
    }
    else {
        window.alert("AJAX (XMLHTTP) not supported.");
    }
    

    I'm not suggesting the above exemplifies best practices (Microsoft seems to have their MSDN examples largely written by very, very inexperienced engineers), but it gives you a starting point. For instance, the above requires that the response status be 200 for success, where of course the HTTP specification is clear that anything the 200 <= n <= 299 range is "success".

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  • 2020-12-01 23:03

    i often use this method for sending and receiving only json in modern browsers (no old-ie's)

    function aj(method, url, data, cb){
    
        var xhr = new XMLHttpRequest();
        xhr.onreadystatechange = readystatechange;
        xhr.open(method, url);
        xhr.setRequestHeader('Content-Type', 'application/json');
        xhr.send(data && JSON.stringify(data));
    
        function readystatechange(){
            if(this.readyState === this.DONE) {
    
                switch(this.status){
                    case 200:
                    if(this.getResponseHeader('Content-Type').split(';')[0] !== 'application/json'){
                        return cb("unexpected Content-Type: '" + this.getResponseHeader('Content-Type') + "'", null);
                    }
                    return cb(null, JSON.parse(this.response));
    
                    case 401:
                    location.href = '/authentication/login';
                    return;
    
                    default:
                    return cb("unexpected status: " + this.status + "", null);
                }
            }
        }//readystatechange
    }
    
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