Pad a number with leading zeros in JavaScript [duplicate]

Answer 1

Not a lot of "slick" going on so far:

function pad(n, width, z) {
  z = z || '0';
  n = n + '';
  return n.length >= width ? n : new Array(width - n.length + 1).join(z) + n;
}

When you initialize an array with a number, it creates an array with the length set to that value so that the array appears to contain that many undefined elements. Though some Array instance methods skip array elements without values, .join() doesn't, or at least not completely; it treats them as if their value is the empty string. Thus you get a copy of the zero character (or whatever "z" is) between each of the array elements; that's why there's a + 1 in there.

Example usage:

pad(10, 4);      // 0010
pad(9, 4);       // 0009
pad(123, 4);     // 0123

pad(10, 4, '-'); // --10

Answer 2

You could do something like this:

function pad ( num, size ) {
  return ( Math.pow( 10, size ) + ~~num ).toString().substring( 1 );
}

Edit: This was just a basic idea for a function, but to add support for larger numbers (as well as invalid input), this would probably be better:

function pad ( num, size ) {
  if (num.toString().length >= size) return num;
  return ( Math.pow( 10, size ) + Math.floor(num) ).toString().substring( 1 );
}

This does 2 things:

1. If the number is larger than the specified size, it will simply return the number.
2. Using Math.floor(num) in place of ~~num will support larger numbers.

Answer 3

You did say you had a number-

String.prototype.padZero= function(len, c){
    var s= '', c= c || '0', len= (len || 2)-this.length;
    while(s.length<len) s+= c;
    return s+this;
}
Number.prototype.padZero= function(len, c){
    return String(this).padZero(len,c);
}