How to convert an Int to a Character in Swift

Question

I\'ve struggled and failed for over ten minutes here and I give in. I need to convert an Int to a Character in Swift and cannot solve it.

Question<

Answer 1

Here is an extension for Int to provide a correspondingLetter function :

extension Int {
    func correspondingLetter(inUppercase uppercase: Bool = false) -> String? {
        let firstLetter = uppercase ? "A" : "a"
        let startingValue = Int(UnicodeScalar(firstLetter)!.value)
        if let scalar = UnicodeScalar(self + startingValue) {
            return String(scalar)
        }
        return nil
    }
}

Note that if the int is larger then 26 you'll get special characters.

Answer 2

You can't convert an integer directly to a Character instance, but you can go from integer to UnicodeScalar to Character and back again:

let startingValue = Int(("A" as UnicodeScalar).value) // 65
for i in 0 ..< 26 {
    print(Character(UnicodeScalar(i + startingValue)))
}