Java: removing numeric values from string

Question

I have suceeded with the help of this community in removing numeric values from user input, however, my code below will only retrieve the alpha characters before the numeric

Answer 1

Your regex:

[^A-Z]

matches anything which is not an uppercase letter.

Which means any lowercase letter will match too.

You should probably use:

[^A-Za-z]

as a regex instead.

Note also that this will not account for anything other than ASCII. It may, or may not, be what you want.

Answer 2

You can use:

firstname1 = firstname1.replaceAll("[0-9]","");

This will remove all numeric values from String firstName1.

    String firstname1 = "S1234am";
    firstname1 = firstname1.replaceAll("[0-9]","");
    System.out.println(firstname1);//Prints Sam

Answer 3

Your regular expression [^A-Z] is currently only configured to preserve upper-case letters. You could try replacing it with [^A-Za-z] to keep the lower-case letters too.

Answer 4

This will remove all digits:

firstname1 = firstname1.replaceAll("\\d","");

Answer 5

public static void main(String[] args) {
    String address = "34732483dhshdsdhajsa8ejdsdd";
    char[] chars = address.toCharArray();
    String aString = "";

    for (int i = 0; i < chars.length; i++) {
        if (!Character.isDigit(chars[i])) {
            aString =aString + chars[i]; 


        }

    }System.out.println(aString);



}

Answer 6

/*Remove numbers from given specific string*/
public class NewClass6 {

    public static void main(String[] args){
        String s= "hello647hi74joke";
        char[] ch= s.toCharArray();
        System.out.println("Result = " + getString(ch));
    }

    static String getString(char[] ch){
        int m = 0;
        char[] chr = new char[50];
        char[] k = {'0','1','2','3','4','5','6','7','8','9'};

        for(int i = 0; i < ch.length; i++){
           for(int j = 0; j < k.length; j++){  
               if(ch[i]==k[j]){
                   m--;
                   break;
               }
               else {
                   chr[m]=ch[i];
               }
            }
            m++;
         }

         String st = String.valueOf(chr);
         return st;
     }
}