Generating random numbers without repeating.C#

Question

Hi everyone I am trying to generate 6 different numbers on the same line in c# but the problem that i face is some of the numbers are repeating on the same line.Here is my c

Answer 1

If you are not worried about the min, max, and range then you can use this.

 var nexnumber = Guid.NewGuid().GetHashCode();
        if (nexnumber < 0)
        {
            nexnumber *= -1;
        }

Answer 2

Make it a while loop and add the integers to a hashset. Stop the loop when you have six integers.

Answer 3

   public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        int[] que = new int[6];
        int x, y, z;
        Random ran = new Random();            
        for ( x = 0; x < 6; x++)
        {
            que[x] = ran.Next(1,49);
            for (y = x; y >= 0; y--)
            {
                if (x == y)
                {
                    continue;
                }
                if (que[x] == que[y])
                {
                    que[x] = ran.Next(1,49);
                    y = x;
                }


            }
        }
        listBox1.Items.Clear();
        for (z = 0; z < 6**strong text**; z++)
        {
            listBox1.Items.Add(que[z].ToString());
        }
    }
}

Answer 4

Paste the below in the class as a new method

    public int randomNumber()
    {
        var random = new Random();
        int randomNumber = random.Next(10000, 99999);
        return randomNumber;
    }

And use the below anywhere in the tests wherever required

var RandNum = randomNumber();

driver.FindElement(By.CssSelector("[class='test']")).SendKeys(**RandNum**);

Answer 5

listNumbers.AddRange(Enumerable.Range(1, 48)
                               .OrderBy(i => rand.Next())
                               .Take(6))