C sizeof a passed array [duplicate]

Answer 1

There is no magic solution. C is not a reflective language. Objects don't automatically know what they are.

But you have many choices:

1. Obviously, add a parameter
2. Wrap the call in a macro and automatically add a parameter
3. Use a more complex object. Define a structure which contains the dynamic array and also the size of the array. Then, pass the address of the structure.

Answer 2

The problem is that your function doesn't receive an array value; it receives a pointer value.

Except when it is the operand of the sizeof or unary & operators, or it is a string literal being used to initialize another array in a declaration, an expression of type "array of T" will be converted to type "pointer to T" and its value will be the address of the first element of the array.

Thus, when you call printarray, the type of array1 is implicitly converted from "100-element array of double" to "pointer to double." Thus, the type of the parameter p is double *, not double [100].

In the context of a function parameter declaration, T a[] is identical to T *a.

This is why you have to pass the array size separately;

Answer 3

You answered your own question. It's computed at compile-time, so how can 'sizeof p' possibly have more than one value during runtime?

Passing the length as a parameter is a fine solution, otherwise you can make sure your arrays always end with some special value (like strings and the null byte).

Answer 4

Function parameters never actually have array type. When the compiler sees

void printarray( double p[], int s )

or even

void printarray( double p[100], int s )

it converts either one to

void printarray( double* p, int s )

So sizeof(p) is sizeof(double*). And yes, you'll have to pass the size as a parameter.

Answer 5

You must either

1. Pass the size of the array as a parameter to the function
2. Ensure that the array ends with a known value, and stop when you reach that value.

Answer 6

If your array is null terminated then you can iterate through the array and find the last value. Many string operators in C work that way

Otherwise you don't have much choice.

sizeof will return the size of p, which is a pointer and will equals to your int size