I need to DELETE
duplicated rows for specified sid on a MySQL
table.
How can I do this with an SQL query?
Another easy way... using UPDATE IGNORE:
U have to use an index on one or more columns (type index). Create a new temporary reference column (not part of the index). In this column, you mark the uniques in by updating it with ignore clause. Step by step:
Add a temporary reference column to mark the uniques:
ALTER TABLE `yourtable` ADD `unique` VARCHAR(3) NOT NULL AFTER `lastcolname`;
=> this will add a column to your table.
Update the table, try to mark everything as unique, but ignore possible errors due to to duplicate key issue (records will be skipped):
UPDATE IGNORE `yourtable` SET `unique` = 'Yes' WHERE 1;
=> you will find your duplicate records will not be marked as unique = 'Yes', in other words only one of each set of duplicate records will be marked as unique.
Delete everything that's not unique:
DELETE * FROM `yourtable` WHERE `unique` <> 'Yes';
=> This will remove all duplicate records.
Drop the column...
ALTER TABLE `yourtable` DROP `unique`;
Deleting duplicates on MySQL tables is a common issue, that usually comes with specific needs. In case anyone is interested, here (Remove duplicate rows in MySQL) I explain how to use a temporary table to delete MySQL duplicates in a reliable and fast way, also valid to handle big data sources (with examples for different use cases).
Ali, in your case, you can run something like this:
-- create a new temporary table
CREATE TABLE tmp_table1 LIKE table1;
-- add a unique constraint
ALTER TABLE tmp_table1 ADD UNIQUE(sid, title);
-- scan over the table to insert entries
INSERT IGNORE INTO tmp_table1 SELECT * FROM table1 ORDER BY sid;
-- rename tables
RENAME TABLE table1 TO backup_table1, tmp_table1 TO table1;
Suppose you have a table employee
, with the following columns:
employee (first_name, last_name, start_date)
In order to delete the rows with a duplicate first_name
column:
delete
from employee using employee,
employee e1
where employee.id > e1.id
and employee.first_name = e1.first_name
This work for me to remove old records:
delete from table where id in
(select min(e.id)
from (select * from table) e
group by column1, column2
having count(*) > 1
);
You can replace min(e.id) to max(e.id) to remove newest records.
This procedure will remove all duplicates (incl multiples) in a table, keeping the last duplicate. This is an extension of Retrieving last record in each group
Hope this is useful to someone.
DROP TABLE IF EXISTS UniqueIDs;
CREATE Temporary table UniqueIDs (id Int(11));
INSERT INTO UniqueIDs
(SELECT T1.ID FROM Table T1 LEFT JOIN Table T2 ON
(T1.Field1 = T2.Field1 AND T1.Field2 = T2.Field2 #Comparison Fields
AND T1.ID < T2.ID)
WHERE T2.ID IS NULL);
DELETE FROM Table WHERE id NOT IN (SELECT ID FROM UniqueIDs);
If you want to keep the row with the lowest id value:
DELETE n1 FROM 'yourTableName' n1, 'yourTableName' n2 WHERE n1.id > n2.id AND n1.email = n2.email
If you want to keep the row with the highest id value:
DELETE n1 FROM 'yourTableName' n1, 'yourTableName' n2 WHERE n1.id < n2.id AND n1.email = n2.email