Get Download URL from file uploaded with Cloud Functions for Firebase

Question

After uploading a file in Firebase Storage with Functions for Firebase, I\'d like to get the download url of the file.

I have this :

...

return buck         


        

Answer 1

This works if you just need a public file with a simple URL. Note that this may overrule your Firebase storage rules.

bucket.upload(file, function(err, file) {
    if (!err) {
      //Make the file public
      file.acl.add({
      entity: 'allUsers',
      role: gcs.acl.READER_ROLE
      }, function(err, aclObject) {
          if (!err) {
              var URL = "https://storage.googleapis.com/[your bucket name]/" + file.id;
              console.log(URL);
          } else {
              console.log("Failed to set permissions: " + err);
          }
      });  
    } else {
        console.log("Upload failed: " + err);
    }
});

Answer 2

This is the best I came up. It is redundant, but the only reasonable solution that worked for me.

await bucket.upload(localFilePath, {destination: uploadPath, public: true});
const f = await bucket.file(uploadPath)
const meta = await f.getMetadata()
console.log(meta[0].mediaLink)

Answer 3

You should avoid harcoding URL prefix in your code, especially when there are alternatives. I suggest using the option predefinedAcl: 'publicRead' when uploading a file with Cloud Storage NodeJS 1.6.x or +:

const options = {
    destination: yourFileDestination,
    predefinedAcl: 'publicRead'
};

bucket.upload(attachment, options);

Then, getting the public URL is as simple as:

bucket.upload(attachment, options).then(result => {
    const file = result[0];
    return file.getMetadata();
}).then(results => {
    const metadata = results[0];
    console.log('metadata=', metadata.mediaLink);
}).catch(error => {
    console.error(error);
});

Answer 4

This is what I currently use, it's simple and it works flawlessly.

You don't need to do anything with Google Cloud. It works out of the box with Firebase..

// Save the base64 to storage.
const file = admin.storage().bucket('url found on the storage part of firebase').file(`profile_photos/${uid}`);
await file.save(base64Image, {
    metadata: {
      contentType: 'image/jpeg',
    },
    predefinedAcl: 'publicRead'
});
const metaData = await file.getMetadata()
const url = metaData[0].mediaLink

EDIT: Same example, but with upload:

await bucket.upload(fromFilePath, {destination: toFilePath});
file = bucket.file(toFilePath);
metaData = await file.getMetadata()
const trimUrl = metatata[0].mediaLink

#update: no need to make two different call in upload method to get the metadata:

let file = await bucket.upload(fromFilePath, {destination: toFilePath});
const trimUrl = file[0].metatata.mediaLink

Answer 5

answer by https://stackoverflow.com/users/269447/laurent works best

const uploadOptions: UploadOptions = {
    public: true
};

const bucket = admin.storage().bucket();
[ffile] = await bucket.upload(oPath, uploadOptions);
ffile.metadata.mediaLink // this is what you need

Answer 6

If you use the predefined access control lists value of 'publicRead', you can upload the file and access it with a very simple url structure:

// Upload to GCS
const opts: UploadOptions = {
  gzip: true,
  destination: dest, // 'someFolder/image.jpg'
  predefinedAcl: 'publicRead',
  public: true
};
return bucket.upload(imagePath, opts);

You can then construct the url like so:

const storageRoot = 'https://storage.googleapis.com/';
const bucketName = 'myapp.appspot.com/'; // CHANGE TO YOUR BUCKET NAME
const downloadUrl = storageRoot + bucketName + encodeURIComponent(dest);